我在一个叫做"购买"的表格中有3列:
id amount price
2 2 21
2 5 9
3 8 5
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我想对具有相似ID的所有行进行分组,并将此数组作为结果:
array([0] => [id => 2, total => 87 (because 2*21+5*9=87)], [1] => [id => 3, total => 40 (because 8*5=40)])
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作为具有相似ID的行的SUM(金额*价格)的总帐户.
我试过用了
SELECT id, SUM(p.price*p.amount) total FROM purchases p GROUP by p.id
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但它不能很好地工作(即它没有实现我想要的,这就是我上面写的).关于如何在mysql中执行此操作的任何想法?
查询返回的示例:
id amount price
2 3 89
2 3 19
SELECT id, SUM(p.price*p.amount) total FROM purchases p GROUP by p.id
==> [id => 2, total => 183]
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Vin*_*rat 17
SELECT
id,
SUM(amount*price) AS total
FROM mytable
GROUP BY id
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数据:
| id | amount | price |
|----|--------|-------|
| 2 | 3 | 19 |
| 2 | 3 | 89 |
| 3 | 203 | 1 |
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结果:
id total
2 324
3 203
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