将消息从线程传递到更新UI

Jay*_*Dee 4 multithreading android messages

我为文件浏览器创建了一个新线程.该线程读取目录的内容.我想要做的是更新UI线程以绘制文件和文件夹的图形表示.我知道我不能在新线程中更新UI所以我想要做的是:

而文件扫描线程遍历目录文件和文件夹将文件路径字符串传递回UI线程.然后,UI线程中的处理程序将绘制传回的​​文件的图形表示.

public class New_Project extends Activity implements Runnable {

    private Handler handler = new Handler() {
        @Override
        public void handleMessage(Message msg) {
            Log.d("New Thread","Proccess Complete.");
            Intent intent = new Intent();
            setResult(RESULT_OK, intent);
            finish();
        }
    };


    public void fileScanner(){
        //if (!XMLEFunctions.canReadExternal(this)) return;
        pd = ProgressDialog.show(this, "Reading Directory.",
                "Please Wait...", true, false);

        Log.d("New Thread","Called");
        Thread thread = new Thread(this);
        thread.start();
    }


    public void run() {
        Log.d("New Thread","Reading Files");
        getFiles();
        handler.sendEmptyMessage(0);
    }


    public void getFiles() {
        for (int i=0;i<=allFiles.length-1;i++){
            //I WANT TO PASS THE FILE PATH BACK TU A HANDLER IN THE UI
            //SO IT CAN BE DRAWN.
            **passFilePathBackToBeDrawn(allFiles[i].toString());**
        } 
    }

}
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Jay*_*Dee 16

似乎传递简单的消息是基于int ...我需要做的是传递一个Bundle

using Message.setData(Bundle) and Message.getData(Bundle)
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好快乐= 0)

//Function From Within The Thread

public void newProjectCreation() {

Message msg =  new Message();
Bundle bundle = new Bundle();

bundle.putString("Test", "test value");
msg.setData(bundle);

handler2.sendMessage(msg);
}

//Handler in The UI Thread Retreieves The Data
//And Can Update the GUI as Required

private Handler handler2 = new Handler() {
    @Override
    public void handleMessage(Message msg) {

    Bundle bundle = msg.getData();
    Toast.makeText(New_Project.this,bundle.getString("Test"),Toast.LENGTH_SHORT).show();

}

};
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