上下文闭包类型'() - > Void'需要0个参数,但在闭包体错误显示中使用了1

Question

   static func animate(_ duration: TimeInterval,
                        animations: (() -> Void)!,
                        delay: TimeInterval = 0,
                        options: UIViewAnimationOptions = [],
                        withComplection completion: (() -> Void)! = {}) {

        UIView.animate(
            withDuration: duration,
            delay: delay,
            options: options,
            animations: {
                animations()
            }, completion: { finished in
                completion()
        })
    }

在我的swift文件中使用上面的类并创建如下所示的函数

SPAnimation.animate(durationScalingRootView,
                        animations: {
                            rootViewController.view.transform = CGAffineTransform.identity
        },
                        delay: delayScalingRootView,
                        options: UIViewAnimationOptions.curveEaseOut,
                        withComplection: {
                            finished in
                            //rootViewController.view.layer.mask = nil
    })

得到此错误

上下文闭包类型'() - > Void'需要0个参数,但在闭包体中使用了1

Answer 1

问题出在这里:

withComplection: {
    finished in
    //rootViewController.view.layer.mask = nil
}

如果查看方法声明,则完成处理程序的类型为(() -> Void)!.它不需要任何论据.你上面的闭包有一个论点 - finished.结果,发生错误.

finished从闭包中删除参数:

withComplection: {
    //rootViewController.view.layer.mask = nil
}

或者您编辑您的animate方法以接受带有一个参数的闭包:

static func animate(_ duration: TimeInterval,
                    animations: (() -> Void)!,
                    delay: TimeInterval = 0,
                    options: UIViewAnimationOptions = [],
                    withComplection completion: ((Bool) -> Void)? = nil) {

    UIView.animate(
        withDuration: duration,
        delay: delay,
        options: options,
        animations: {
            animations()
        }, completion: { finished in
            completion?(finished)
    })
}