Jar*_*rod 2 mysql left-join multiple-tables
我有个问题。我有4张桌子:
Invoice_Payment、发票、客户和日历
基本上,我有以下查询,效果很好,除了没有 date_due 的月份不会返回。IE 只会返回带有 date_due 的月份。
注意:日历表只列出一年中的每一天。它包含一个 col 调用 date_field
数据库:http : //oberto.co.nz/jInvoice.txt
预期输出:下面我当前的查询将返回如下内容:
month total
August 5
September 0
October 196
November 205
December 214
January 229
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请注意九月没有返回?这是因为表 Invoice_Payment 没有 date_due 记录
我想我必须使用左联接并加入日历表,例如:LEFT JOIN Calendar ON Invoice_Payments.date_paid = Calendar.date_field。但我没有运气
SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total
FROM Invoice, Client, Invoice_Payments
WHERE Client.registered_id = 1
AND Client.id = Invoice.client_id
And Invoice.id = Invoice_Payments.invoice_id
AND date_paid IS NOT NULL
GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid)
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任何帮助表示赞赏。
听起来您正在尝试查找范围内所有日期的值,而不管是否有值。假设我们有一个结构如下的日历表:
Create Table Calendar
(
[Date] not null Primary Key
)
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您的查询可能如下所示(其中 X 和 Y 表示您正在调查的范围的开始和结束日期):
Select Year(C.Date), MonthName(C.Date) As Month
, Coalesce(Sum(IP.paid_amount),0) As Total
From Calendar As C
Left Join (Invoice As I
Join Client As C1
On C1.id = I.client_id
And C.registered_id = 1
Join Invoice_Payments As IP
On IP.Invoice_id = I.Id)
On IP.date_paid = C.date
Where C.Date Between X and Y
Group By Year(C.Date), MonthName(C.Date)
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从技术上讲,上面的查询应该可以解决问题。但是,另一种选择是使用您在评论中查询的派生表:
Select Year(C.Date), MonthName(C.Date) As Month
, Coalesce(Sum(Z.paid_amount),0) As Total
From Calendar As C
Left Join (
Select IP.date_paid, IP.paid_amount
From Invoice As I
Join Client As C1
On C1.id = I.client_id
And C.registered_id = 1
Join Invoice_Payments As IP
On IP.Invoice_id = I.Id
) As Z
On Z.date_paid = C.date
Where C.Date Between X and Y
Group By Year(C.Date), MonthName(C.Date)
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