如何从JSON对象获取简单数据

Question

如何从此对象获取值？

var descipt = "{'type':'" + $('#medi-type option:selected').val() +"',"+
        "'weight':" + $('#weight').val() +","+
        "'weight-type':'" + $('#weight-type option:selected').val() +"',"+
        "'dose':'" + $('#medicine-dose').val() +"',"+
        "'dose-type':'" + $('#dose-type option:selected').val() +"',"+
        "'day-time':'" + morning +"',"+
        "'noon-time':'" + noon +"',"+
        "'night-time':'" + night +"',"+
        "'after':'" + after +"',"+
        "'before':'" + before +"'}";

alert(descipt.weight);

如何从物体上获得重量.

Answer 1

那不是JSON对象,那是一个字符串.您应该先将其解析为JSON对象

var desciptObject = JSON.parse(descipt);

然后你可以阅读体重

weight = desciptObject.weight;