elisp:对当前文件的call命令

Question

我想在emacs中设置一个键,对缓冲区中的文件执行shell命令,并在不提示的情况下恢复缓冲区.shell命令是:p4 edit 'currentfilename.ext'

(global-set-key [\C-E] (funcall 'revert-buffer 1 1 1)) 
;; my attempt above to call revert-buffer with a non-nil 
;; argument (ignoring the shell command for now) -- get an init error:
;; Error in init file: error: "Buffer does not seem to be associated with any file"

完全是elisp新手.从emacs手册中,这里是revert-buffer的定义:

Command: revert-buffer &optional ignore-auto noconfirm preserve-modes

谢谢!

Answer 1

您看到的实际错误是因为您错误地指定了global-set-key,即函数调用.你想要的是:

(global-set-key (kbd "C-S-e") '(lambda () (revert-buffer t t t)))

您funcall实际上在评估.emacs何时加载时,这是导致错误的原因.

然后,为了获得整个事情,您可以创建一个命令,如:

(defun call-something-on-current-buffers-file ()
  "run a command on the current file and revert the buffer"
  (interactive)
  (shell-command 
   (format "/home/tjackson/bin/dummy.sh %s" 
       (shell-quote-argument (buffer-file-name))))
  (revert-buffer t t t))
(global-set-key (kbd "C-S-e") 'call-something-on-current-buffers-file)

显然,自定义命令,并根据需要添加错误检查.