如何在C#中处理Telegram bot上的多个用户？

Question

我写了一个机器人,询问你的名字并将其写在照片上并发送给你并且它有效.但问题是当僵尸程序上有多个用户时
它无法正常工作并崩溃,我想知道如何分离用户条目和输出.(就像每个连接的用户得到一个单独的会话,因为现在一切都发生在一个会话和它崩溃)这是我的代码:

    void bot_OnMessage(object sender, Telegram.Bot.Args.MessageEventArgs e)
    {
     KeyboardButton[] btns = new KeyboardButton[1];
     btns[0] = new KeyboardButton("???? ???");
        if(e.Message.Text=="???? ???")
        {
            bot.SendTextMessageAsync(e.Message.From.Id, "??? ??? ?? ???? ????", Telegram.Bot.Types.Enums.ParseMode.Default, false, false, 0);
           // e.Message.Text = null;
            shart = 1;

        }
        else
        {
            if (shart == 0)
            {
                Telegram.Bot.Types.ReplyMarkups.ReplyKeyboardMarkup markup = new Telegram.Bot.Types.ReplyMarkups.ReplyKeyboardMarkup(btns);

                bot.SendTextMessageAsync(e.Message.From.Id, "???? ???? ? ???? ??? ??? ???? ???? ??? ???? ????", Telegram.Bot.Types.Enums.ParseMode.Default, false, false, 0, markup);
            }
            if (shart==1)
            {
                bot.StartReceiving();
                bot.OnMessage += bot_OnMessage1;
            }
        }
    }

    void bot_OnMessage1(object sender, Telegram.Bot.Args.MessageEventArgs a)
    {
        string watermarkText = a.Message.Text;

        //Get the file name.
        string fileName = "C:\\temp\\01.jpg";

        //Read the File into a Bitmap.
        using (Bitmap bmp = new Bitmap(fileName))
        {
            using (Graphics grp = Graphics.FromImage(bmp))
            {
                //Set the Color of the Watermark text.
                Brush brush = new SolidBrush(Color.White);

                //Set the Font and its size.
                Font font = new System.Drawing.Font("Arial", 50, FontStyle.Bold, GraphicsUnit.Pixel);

                //Determine the size of the Watermark text.
                SizeF textSize = new SizeF();
                textSize = grp.MeasureString(watermarkText, font);

                //Position the text and draw it on the image.
                Point position = new Point((bmp.Width - ((int)textSize.Width + 10)), (bmp.Height - ((int)textSize.Height + 10)));
                grp.DrawString(watermarkText, font, brush, position);
                bmp.Save("c:\\temp\\postpic.jpg", ImageFormat.Png);

                using (FileStream fs = new FileStream("c:\\temp\\postpic.jpg", FileMode.Open))
                {

                    fs.CanTimeout.ToString();
                    FileToSend fileToSend = new FileToSend("postpic.jpg", fs);
                    //  var =   FileToSend fts = new FileToSend("postpic", fs);
                    var rep = bot.SendPhotoAsync(a.Message.From.Id, fileToSend, "??? ??? ?? ??? ????").Result;

                }
            }
        }
    }
}

Answer 1

您正在为每个用户编写(并随后读取)相同的文件:

mp.Save("c:\\temp\\postpic.jpg"

您需要为每个用户提供唯一的文件名.或者更好的是,根本不要使用文件.您可能只是使用本地内存流而根本不会使用文件混乱磁盘.