类型'Observable <DataSnapshot>'上不存在属性'unsubscribe'

Question

Typescript(原子编辑器中的tslint)给了我一个打字稿错误,但我无法弄清楚如何设置正确的类型.

错误信息:

聊天组件:

  private _chatObserver: Observable<firebase.database.DataSnapshot>

  otherMethod () {
        this._chatObserver = this._chat.observe(alarmId)
        this._chatObserver.subscribe(
          (messageSnap: firebase.database.DataSnapshot) => {
            this.messages.push(messageSnap.val())
          },
          error => {throw error})
    }

    ionViewDidLeave() {
       this._chatObserver.unsubscribe() 
    }

_chat提供者:

  public observe (alarmId){
    let messagesRef = this._ref.child(`alarms/${alarmId}/messages`)

    const observable = Observable.create(observer => {
      messagesRef.on('child_added',(messageSnap) => {
            observer.next(messageSnap)
        },
        (error) => observer.error(error)
      )
      return () => {
        messagesRef.off('value')
      };
    });

    return observable
  }

Answer 1

Unsubscribe是订阅本身的一种方法.因此,在顶部添加:

private _chatSubscription;

然后在你的otherMethod:

this._chatSubscription = this._chatObserver.subscribe(...);

在你的destroy/leave/termination处理程序中:

this._chatSubscription.unsubscribe();

Answer 2

试试这个

private _chatObserver: Observable<firebase.database.DataSnapshot>
private _subscription:Subscription
otherMethod () {
    this._chatObserver = this._chat.observe(alarmId)
    this._subscription=this._chatObserver.subscribe(
      (messageSnap: firebase.database.DataSnapshot) => {
        this.messages.push(messageSnap.val())
      },
      error => {throw error})
}

ionViewDidLeave() {
   this._subscription.unsubscribe() 
}