有没有人知道如何获得相当于jQuery .offset()和.closest()没有JavaScript库的东西?
因为.closest(),如果我知道爬上DOM树有多远,我可以使用那么多.parentNodes,但如果我不知道要走多远,我就会陷入困境.
jQuery的核心是javascript.您可以使用此jQuery源查看器来查找任何方法的实现.
例如,以下是如何closest实现:
closest: function( selectors, context ) {
var ret = [], i, l, cur = this[0];
if ( jQuery.isArray( selectors ) ) {
var match, selector,
matches = {},
level = 1;
if ( cur && selectors.length ) {
for ( i = 0, l = selectors.length; i < l; i++ ) {
selector = selectors[i];
if ( !matches[selector] ) {
matches[selector] = jQuery.expr.match.POS.test( selector ) ?
jQuery( selector, context || this.context ) :
selector;
}
}
while ( cur && cur.ownerDocument && cur !== context ) {
for ( selector in matches ) {
match = matches[selector];
if ( match.jquery ? match.index(cur) > -1 : jQuery(cur).is(match) ) {
ret.push({ selector: selector, elem: cur, level: level });
}
}
cur = cur.parentNode;
level++;
}
}
return ret;
}
var pos = POS.test( selectors ) ?
jQuery( selectors, context || this.context ) : null;
for ( i = 0, l = this.length; i < l; i++ ) {
cur = this[i];
while ( cur ) {
if ( pos ? pos.index(cur) > -1 : jQuery.find.matchesSelector(cur, selectors) ) {
ret.push( cur );
break;
} else {
cur = cur.parentNode;
if ( !cur || !cur.ownerDocument || cur === context ) {
break;
}
}
}
}
ret = ret.length > 1 ? jQuery.unique(ret) : ret;
return this.pushStack( ret, "closest", selectors );
}
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以下是执行offset:
jQuery.fn.offset = function( options ) {
var elem = this[0], box;
if ( options ) {
return this.each(function( i ) {
jQuery.offset.setOffset( this, options, i );
});
}
if ( !elem || !elem.ownerDocument ) {
return null;
}
if ( elem === elem.ownerDocument.body ) {
return jQuery.offset.bodyOffset( elem );
}
try {
box = elem.getBoundingClientRect();
} catch(e) {}
var doc = elem.ownerDocument,
docElem = doc.documentElement;
// Make sure we're not dealing with a disconnected DOM node
if ( !box || !jQuery.contains( docElem, elem ) ) {
return box || { top: 0, left: 0 };
}
var body = doc.body,
win = getWindow(doc),
clientTop = docElem.clientTop || body.clientTop || 0,
clientLeft = docElem.clientLeft || body.clientLeft || 0,
scrollTop = (win.pageYOffset || jQuery.support.boxModel && docElem.scrollTop || body.scrollTop ),
scrollLeft = (win.pageXOffset || jQuery.support.boxModel && docElem.scrollLeft || body.scrollLeft),
top = box.top + scrollTop - clientTop,
left = box.left + scrollLeft - clientLeft;
return { top: top, left: left };
};
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