zen*_*337 6 java login spring-security jwt auth0
我正在遵循这个auth0的教程来使用JWT来保护我的应用程序.
我最终得到了以下WebSecurity配置:
@EnableWebSecurity
@AllArgsConstructor(onConstructor = @__(@Autowired))
public class WebSecurity extends WebSecurityConfigurerAdapter {
private final UserDetailsService userDetailsService;
private final BCryptPasswordEncoder passwordEncoder;
@Override
protected void configure(HttpSecurity http) throws Exception {
http.formLogin()
.and().cors()
.and().csrf()
.disable()
.authorizeRequests()
.antMatchers(HttpMethod.POST, REGISTER_URL).permitAll()
.antMatchers(HttpMethod.POST, LOGIN_URL).permitAll()
.anyRequest().authenticated()
.and()
.addFilter(new JWTAuthorizationFilter(authenticationManager()))
.addFilter(new JWTAuthenticationFilter(authenticationManager()))
// This disables session creation on Spring Security
.sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS);
}
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.userDetailsService(userDetailsService).passwordEncoder(passwordEncoder);
}
@Bean
public CorsConfigurationSource corsConfigurationSource() {
final UrlBasedCorsConfigurationSource source = new UrlBasedCorsConfigurationSource();
source.registerCorsConfiguration("/**", new CorsConfiguration().applyPermitDefaultValues());
return source;
}
}
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和以下JWTAuthenticationFilter:
public class JWTAuthenticationFilter extends UsernamePasswordAuthenticationFilter {
private final AuthenticationManager authenticationManager;
public JWTAuthenticationFilter(AuthenticationManager authenticationManager) {
this.authenticationManager = authenticationManager;
}
@Override
public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response) throws AuthenticationException {
try {
ApplicationUser credentials = new ObjectMapper().readValue(request.getInputStream(), ApplicationUser.class);
return authenticationManager.authenticate(
new UsernamePasswordAuthenticationToken(
credentials.getUsername(),
credentials.getPassword(),
new ArrayList<>()
)
);
} catch (IOException e) {
throw new RuntimeException(e);
}
}
@Override
protected void successfulAuthentication(HttpServletRequest request, HttpServletResponse response, FilterChain chain, Authentication authResult) throws IOException, ServletException {
String token = Jwts.builder()
.setSubject(((User) authResult.getPrincipal()).getUsername())
.setExpiration(new Date(System.currentTimeMillis() + EXPIRATION_TIME))
.signWith(SignatureAlgorithm.HS512, SECRET.getBytes())
.compact();
response.addHeader(HEADER_STRING, TOKEN_PREFIX + token);
}
}
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目前,该应用程序接受/loginURL 上的POST请求.我想知道如何更改URL,比如说/api/auth/login.有没有办法将URL字符串注入验证过滤器或在安全配置中以某种方式设置它?
jlu*_*etu 20
您正在扩展org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter,它本身扩展了
org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.在最后一个类中,有一个setter setFilterProcessesUrl,它的目的就是:
setFilterProcessesUrl
public void setFilterProcessesUrl(String filterProcessesUrl)
设置确定是否需要身份验证的URL
参数:filterProcessesUrl
这是该javadoc部分的链接
所以WebSecurityConfigurerAdapter你可以这样做:
@Bean
public JWTAuthenticationFilter getJWTAuthenticationFilter() {
final JWTAuthenticationFilter filter = new JWTAuthenticationFilter(authenticationManager());
filter.setFilterProcessesUrl("/api/auth/login");
return filter;
}
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然后在configure同一个类中的方法中引用它而不是创建新实例:
.addFilter(getJWTAuthenticationFilter())
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