在Spring Security UsernamePasswordAuthenticationFilter JWT身份验证中设置自定义登录URL

zen*_*337 6 java login spring-security jwt auth0

我正在遵循这个auth0的教程来使用JWT来保护我的应用程序.

我最终得到了以下WebSecurity配置:

@EnableWebSecurity
@AllArgsConstructor(onConstructor = @__(@Autowired))
public class WebSecurity extends WebSecurityConfigurerAdapter {

    private final UserDetailsService userDetailsService;
    private final BCryptPasswordEncoder passwordEncoder;

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.formLogin()
                .and().cors()
                .and().csrf()
                .disable()
                .authorizeRequests()
                .antMatchers(HttpMethod.POST, REGISTER_URL).permitAll()
                .antMatchers(HttpMethod.POST, LOGIN_URL).permitAll()
                .anyRequest().authenticated()
                .and()
                .addFilter(new JWTAuthorizationFilter(authenticationManager()))
                .addFilter(new JWTAuthenticationFilter(authenticationManager()))
                // This disables session creation on Spring Security
                .sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS);
    }

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userDetailsService).passwordEncoder(passwordEncoder);
    }

    @Bean
    public CorsConfigurationSource corsConfigurationSource() {
        final UrlBasedCorsConfigurationSource source = new UrlBasedCorsConfigurationSource();
        source.registerCorsConfiguration("/**", new CorsConfiguration().applyPermitDefaultValues());
        return source;
    }

}
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和以下JWTAuthenticationFilter:

public class JWTAuthenticationFilter extends UsernamePasswordAuthenticationFilter {

    private final AuthenticationManager authenticationManager;

    public JWTAuthenticationFilter(AuthenticationManager authenticationManager) {
        this.authenticationManager = authenticationManager;
    }

    @Override
    public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response) throws AuthenticationException {
        try {
            ApplicationUser credentials = new ObjectMapper().readValue(request.getInputStream(), ApplicationUser.class);
            return authenticationManager.authenticate(
                    new UsernamePasswordAuthenticationToken(
                            credentials.getUsername(),
                            credentials.getPassword(),
                            new ArrayList<>()
                    )
            );
        } catch (IOException e) {
            throw new RuntimeException(e);
        }
    }

    @Override
    protected void successfulAuthentication(HttpServletRequest request, HttpServletResponse response, FilterChain chain, Authentication authResult) throws IOException, ServletException {
        String token = Jwts.builder()
                .setSubject(((User) authResult.getPrincipal()).getUsername())
                .setExpiration(new Date(System.currentTimeMillis() + EXPIRATION_TIME))
                .signWith(SignatureAlgorithm.HS512, SECRET.getBytes())
                .compact();
        response.addHeader(HEADER_STRING, TOKEN_PREFIX + token);
    }
}
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目前,该应用程序接受/loginURL 上的POST请求.我想知道如何更改URL,比如说/api/auth/login.有没有办法将URL字符串注入验证过滤器或在安全配置中以某种方式设置它?

jlu*_*etu 20

您正在扩展org.springframework.security.web.authentication.UsernamePasswordAuthenticationFilter,它本身扩展了 org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.在最后一个类中,有一个setter setFilterProcessesUrl,它的目的就是:

setFilterProcessesUrl

public void setFilterProcessesUrl(String filterProcessesUrl)

设置确定是否需要身份验证的URL

参数:filterProcessesUrl

是该javadoc部分的链接

所以WebSecurityConfigurerAdapter你可以这样做:

@Bean
public JWTAuthenticationFilter getJWTAuthenticationFilter() {
    final JWTAuthenticationFilter filter = new JWTAuthenticationFilter(authenticationManager());
    filter.setFilterProcessesUrl("/api/auth/login");
    return filter;
}
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然后在configure同一个类中的方法中引用它而不是创建新实例:

.addFilter(getJWTAuthenticationFilter())
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