Aam*_*ikh 6 javascript php ajax jquery autocomplete
我正在使用PHP进行自动完成,但我收到以下代码的错误,所以请帮助我.
的index.php
这是我的HTML代码
<form method="POST">
<input type="text" name="txtpname" id="txtpname" size="30" class="form-control" placeholder="Please Enter City or ZIP code">
</form>
Run Code Online (Sandbox Code Playgroud)
这是我的剧本
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.18/jquery-ui.min.js"></script>
<link rel="stylesheet" type="text/css" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" />
<script type="text/javascript">
$(document).ready(function(){
$("#txtpname").autocomplete({
source:'ajax_autocomplete_party.php',
minLength:1
});
});
</script>
Run Code Online (Sandbox Code Playgroud)
这是我获取数据的ajax文件.ajax_autocomplete_party.php
包括"script/db.php";
$term=$_GET["txtpname"];
$query=mysql_query("SELECT * FROM party_details where NAME like '%".$term."%' order by NAME");
$json=array();
while($party=mysql_fetch_array($query))
{
$json[]=array(
'value'=> $party["PARTY_ID"],
'label'=>$party["NAME"]
);
}
echo json_encode($json);
Run Code Online (Sandbox Code Playgroud)
我的页面重新加载错误时出现错误:autocomplete not defined现在该怎么办
最新版本的 jQuery 和 -UI 使其可以工作:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
Run Code Online (Sandbox Code Playgroud)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
Run Code Online (Sandbox Code Playgroud)
$(document).ready(function() {
$("#txtpname").autocomplete({
source: [
"ActionScript",
"AppleScript",
"Asp",
"BASIC",
"C",
"C++",
"Clojure",
"COBOL",
"ColdFusion",
"Erlang",
"Fortran",
"Groovy",
"Haskell",
"Java",
"JavaScript",
"Lisp",
"Perl",
"PHP",
"Python",
"Ruby",
"Scala",
"Scheme"
],
minLength: 1
});
});Run Code Online (Sandbox Code Playgroud)