tua*_*562 5 java spring hibernate jpa many-to-one
我有两种模型:第一
类:
import javax.persistence.*;
import java.util.Set;
@Entity
public class One {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String name;
@OneToMany(mappedBy = "one")
private Set<Many> manySet;
//Constructor, Getter and Setter
}
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许多类:
import javax.persistence.*;
@Entity
public class Many {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;
private String name;
@ManyToOne
@JoinColumn(name = "one_id")
private One one;
//Constructor, Getter and Setter
}
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仓库:
import com.hotel.model.Many;
import org.springframework.data.jpa.repository.JpaRepository;
public interface ManyRepository extends JpaRepository<Many, Long> {
}
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控制器类别:
@RestController
@RequestMapping(value = "many")
public class ManyController {
@Autowired
private ManyRepository manyRepository;
@GetMapping
@ResponseBody
public List<Many> getAllMany() {
return manyRepository.findAll();
}
@PostMapping
@ResponseBody
public ResponseEntity createMany(@RequestBody Many many) {
return new ResponseEntity(manyRepository.save(many), HttpStatus.CREATED);
}
}
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我创建了一条ID为1的记录。但是,当我使用JSON数据创建Many记录时:
{
"name": "Foo",
"one_id": 1
}
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我收到的one_id是多个记录null
可以仅使用一个请求来创建新的许多记录并分配给ID为1的一个记录吗?我是否必须使用2个请求:创建多个并分配给一个?
你必须像这样更新你的方法
@PostMapping
@ResponseBody
public ResponseEntity createMany(@RequestBody ManyDTO many) {
One one = oneRepository(many.getOne_id()); //Get the parent Object
Many newMany = new Many(); //Create a new Many object
newMany.setName(many.getName());
newMany.setOne(one); // Set the parent relationship
...
}
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注:以上答案仅解释了实体关系的设置方法。实际应该调用正确的服务层。
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