C＃似乎无法正确将图像添加到ziparchive

Question

我正在尝试在c＃中将一堆文件添加到zip文件中，但是它似乎无法正常工作。

using (var memoryStream = new MemoryStream())
{
    using (var zip = new ZipArchive(memoryStream, ZipArchiveMode.Create, true))
    {
        for (int i = 0; i < kaart_data.GetLength(0); i++)
        {
            Image img = array[i];

            var file = zip.CreateEntry(i + ".bmp");
            using (var stream = new MemoryStream())
            {
                img.Save(stream, ImageFormat.Bmp);
                using (var entryStream = file.Open())
                {
                    stream.CopyTo(entryStream);
                }
            }
        }
    }

    //saves the archive to disk
    using (var fileStream = new FileStream(@"C:\Temp\test.zip", FileMode.Create))
    {
        memoryStream.Seek(0, SeekOrigin.Begin);
        memoryStream.CopyTo(fileStream);
    }
}

问题是它确实会创建zip文件并将其以预期的文件大小保存到磁盘中。

但是，当我尝试在Windows Photo Viewer中打开它们时，它们似乎已损坏。

任何帮助表示赞赏。

Answer 1

几乎花了3个小时才弄清楚问题所在。如果您查看原始图像的大小并提取出原始图像的大小，则存在微小差异。

using (var memoryStream = new MemoryStream())
{
    using (var zip = new ZipArchive(memoryStream, ZipArchiveMode.Create, true))
    {
        for (var i = 0; i < images.Length; i++)
        {
            var img = images[i];
            var file = zip.CreateEntry(i + ".bmp");
            using (var stream = new MemoryStream())
            {
                img.Save(stream, ImageFormat.Bmp);
                using (var entryStream = file.Open())
                {
                    var bytes = stream.ToArray(); -- to keep it as image better to have it as bytes
                    entryStream.Write(bytes, 0, bytes.Length); 
                }
            }
        }
    }

    using (var fileStream = new FileStream(@"test.zip", FileMode.Create))
    {
        memoryStream.Seek(0, SeekOrigin.Begin);
        memoryStream.CopyTo(fileStream);
    }
}

我已经尝试过了，它就像一种魅力！