检测ListView上的手势有问题

Question

我有一个包含ViewFlipper的Activity.ViewFlipper包含2个布局,这两个布局基本上只是ListView.

所以这里的想法是我有两个列表,从一个列表导航到另一个列表,我会使用水平滑动.

我有那个工作.但是,当滑动开始执行时,您的手指所在的列表项目,也会长按该项目.

这是我的相关代码:

public class MyActivity extends Activity implements OnItemClickListener, OnClickListener {

    private static final int SWIPE_MIN_DISTANCE = 120;
    private static final int SWIPE_MAX_OFF_PATH = 250;
    private static final int SWIPE_THRESHOLD_VELOCITY = 200;

    private GestureDetector mGestureDetector;
    View.OnTouchListener mGestureListener;

    class MyGestureDetector extends SimpleOnGestureListener {
        @Override
        public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX, float velocityY) {
            try {
                if (Math.abs(e1.getY() - e2.getY()) > SWIPE_MAX_OFF_PATH)
                    return false;
                // right to left swipe
                if(e1.getX() - e2.getX() > SWIPE_MIN_DISTANCE && Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY) {
                    if (mCurrentScreen != SCREEN_SECONDLIST) {
                        mCurrentScreen = SCREEN_SECONDLIST;
                        mFlipper.setInAnimation(inFromRightAnimation());
                        mFlipper.setOutAnimation(outToLeftAnimation());
                        mFlipper.showNext();
                        updateNavigationBar();
                    }
                }
                else if (e2.getX() - e1.getX() > SWIPE_MIN_DISTANCE && Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY) {
                    if (mCurrentScreen != SCREEN_FIRSTLIST) {
                        mCurrentScreen = SCREEN_FIRSTLIST;
                        mFlipper.setInAnimation(inFromLeftAnimation());
                        mFlipper.setOutAnimation(outToRightAnimation());
                        mFlipper.showPrevious();
                        updateNavigationBar();
                    }
                }
            } catch (Exception e) {
                // nothing
            }
            return true;
        }
    }

    @Override
    public boolean onTouchEvent(MotionEvent event) {
        if (mGestureDetector.onTouchEvent(event))
            return true;
        else
            return false;
    }





    ViewFlipper mFlipper;

    private int mCurrentScreen = SCREEN_FIRSTLIST;

    private ListView mList1;
    private ListView mList2;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        requestWindowFeature(Window.FEATURE_NO_TITLE);
        setContentView(R.layout.layout_flipper);

        mFlipper = (ViewFlipper) findViewById(R.id.flipper);

        mGestureDetector = new GestureDetector(new MyGestureDetector());
        mGestureListener = new View.OnTouchListener() {
            public boolean onTouch(View v, MotionEvent event) {
                if (mGestureDetector.onTouchEvent(event)) {
                    return true;
                }
                return false;
            }
        };

        // set up List1 screen

        mList1List = (ListView)findViewById(R.id.list1);
        mList1List.setOnItemClickListener(this);
        mList1List.setOnTouchListener(mGestureListener);

        // set up List2 screen
        mList2List = (ListView)findViewById(R.id.list2);
        mList2List.setOnItemClickListener(this);
        mList2List.setOnTouchListener(mGestureListener);

    }

    …
}

如果我改变"return true;" 从GestureDetector声明"返回false;",我没有得到长按.不幸的是,我经常点击.

有谁知道我怎么能解决这个问题？

Answer 1

只是用完全不同的方法提出一个完全不同的答案......

我做了一个名为SwipeView的自定义视图,它是开源等等等等等等等等等等.它应该让你做你想做的事情就像去:

mSwipeView.addChild(myList1);
mSwipeView.addChild(myList2);

您不必乱用手势探测器或任何东西,滑动应该按照您的手指操作...

(这听起来像一个可怕的可怕广告,请原谅.这是漫长的一天;)

有一些很棒的链接:

http://jasonfry.co.uk/?id=23

http://jasonfry.co.uk/?id=24

http://jasonfry.co.uk/?id=28