将CURL转换为URLRequest

Question

我正在尝试将以下curl请求Swagger转换为URLRequest：

curl -X GET --header 'Accept: application/json' 
--header 'Authorization: key ttn-account-v2.<app-key>'
 'https://<app-id>.data.thethingsnetwork.org/api/v2/query'

URL和标题设置正确。我仍然收到响应：401-未经授权。

let key = "ttn-account-v2.<app-key>"

let url = URL(string: "https://<app-id>.data.thethingsnetwork.org/api/v2/query")

var request = URLRequest(url: url!)

request.httpMethod = "GET"
request.addValue("application/json", forHTTPHeaderField: "Accept")
request.addValue("key \(key)", forHTTPHeaderField: "Authorization")

let task = URLSession.shared.dataTask(with: url!) { data, response, error in
    guard error == nil else {
        print(error!)
        return
    }
    guard let data = data else {
        print("Data is empty")
        return
    }

    let json = try! JSONSerialization.jsonObject(with: data, options: [])
    print(json)
}
task.resume()

我想念什么吗？

Answer 1

出问题的是，您创建了一个完美的请求，但是dataTask仅对URL而不是对请求进行了处理，从而跳过了所有请求。这种方式HTTPHeaders不会随请求一起发送，因此未经授权。只需将任务创建行更改为此：

let task = URLSession.shared.dataTask(with: req) { data, response, error in 
    ...
}