填充以下用户mongoose

Question

Lemme花时间解释从开始到结束发生的事情.

序言:

用户a跟随其他10个人.当用户A登录时,来自10个人中的每个人的X个帖子被拉入视野中.

我不知道这是否是正确的做法,并会欣赏更好的方法.但是,我想尝试一下,它不起作用.

关注型号:

let mongoose = require('mongoose');
let Schema = mongoose.Schema;

let FollowSchema = new Schema({
  user: {
    type: Schema.Types.ObjectId,
    ref: 'User'
  },
  followers: [{
    type: Schema.Types.ObjectId,
    ref: 'Card'
  }],
  following: [{
    type: Schema.Types.ObjectId,
    ref: 'Card'
  }]
});

module.exports = mongoose.model('Follow', FollowSchema);

卡模型

let mongoose = require('mongoose');
let Schema = mongoose.Schema;

let CardSchema = new Schema({
  title: String,
  content: String,
  createdById: {
    type: Schema.Types.ObjectId,
    ref: 'User'
  },
  createdBy: {
    type: String
  }
});

module.exports = mongoose.model('Card', CardSchema);

遵循逻辑

当用户A跟随用户B时,做两件事:

• 将B的user_id推送到"跟随"字段的用户A文档(A跟随B)

• 将A的user_id推送到字段'关注者'上的用户B文档(B后跟A)

  router.post('/follow', utils.loginRequired, function(req, res) {
  const user_id = req.user._id;
  const follow = req.body.follow_id;
  
  let bulk = Follow.collection.initializeUnorderedBulkOp();
  
  bulk.find({ 'user': Types.ObjectId(user_id) }).upsert().updateOne({
      $addToSet: {
          following: Types.ObjectId(follow)
      }
  });
  
  bulk.find({ 'user': Types.ObjectId(follow) }).upsert().updateOne({
      $addToSet: {
          followers: Types.ObjectId(user_id)
      }
  })
  
  bulk.execute(function(err, doc) {
      if (err) {
          return res.json({
              'state': false,
              'msg': err
          })
      }
      res.json({
          'state': true,
          'msg': 'Followed'
      })
  })
  

  })

实际DB值

> db.follows.find().pretty()
{
    "_id" : ObjectId("59e3e27dace1f14e0a70862d"),
    "user" : ObjectId("59e2194177cae833894c9956"),
    "following" : [
        ObjectId("59e3e618ace1f14e0a708713")
    ]
}
{
    "_id" : ObjectId("59e3e27dace1f14e0a70862e"),
    "user" : ObjectId("59e13b2dca5652efc4ca2cf5"),
    "followers" : [
        ObjectId("59e2194177cae833894c9956"),
        ObjectId("59e13b2d27cfed535928c0e7"),
        ObjectId("59e3e617149f0a3f1281e849")
    ]
}
{
    "_id" : ObjectId("59e3e71face1f14e0a708770"),
    "user" : ObjectId("59e13b2d27cfed535928c0e7"),
    "following" : [
        ObjectId("59e3e618ace1f14e0a708713"),
        ObjectId("59e13b2dca5652efc4ca2cf5"),
        ObjectId("59e21942ca5652efc4ca30ab")
    ]
}
{
    "_id" : ObjectId("59e3e71face1f14e0a708771"),
    "user" : ObjectId("59e3e618ace1f14e0a708713"),
    "followers" : [
        ObjectId("59e13b2d27cfed535928c0e7"),
        ObjectId("59e2194177cae833894c9956")
    ]
}
{
    "_id" : ObjectId("59e3e72bace1f14e0a708779"),
    "user" : ObjectId("59e21942ca5652efc4ca30ab"),
    "followers" : [
        ObjectId("59e13b2d27cfed535928c0e7"),
        ObjectId("59e2194177cae833894c9956"),
        ObjectId("59e3e617149f0a3f1281e849")
    ]
}
{
    "_id" : ObjectId("59f0eef155ee5a5897e1a66d"),
    "user" : ObjectId("59e3e617149f0a3f1281e849"),
    "following" : [
        ObjectId("59e21942ca5652efc4ca30ab"),
        ObjectId("59e13b2dca5652efc4ca2cf5")
    ]
}
> 

有了上面的数据库结果,这是我的查询:

询问

router.get('/follow/list', utils.loginRequired, function(req, res) {
    const user_id = req.user._id;

    Follow.findOne({ 'user': Types.ObjectId(user_id) })
      .populate('following')
      .exec(function(err, doc) {
          if (err) {
              return res.json({
                  'state': false,
                  'msg': err
              })
          };

          console.log(doc.username);

          res.json({
              'state': true,
              'msg': 'Follow list',
              'doc': doc
          })
      })
});

通过上面的查询,从我对Mongoose populate的一点了解,我希望从following阵列中的每个用户获得卡片.

我的理解和期望可能是错误的,但是如果有这样的结果,这种填充方法是否还可以？或者我是否尝试用人口来解决聚合任务？

更新:

谢谢你的回答.变得非常接近但仍然followingCards没有结果.这是我当前Follow模型的内容:

> db.follows.find().pretty()
{
    "_id" : ObjectId("59f24c0555ee5a5897e1b23d"),
    "user" : ObjectId("59f24bda1d048d1edad4bda8"),
    "following" : [
        ObjectId("59f24b3a55ee5a5897e1b1ec"),
        ObjectId("59f24bda55ee5a5897e1b22c")
    ]
}
{
    "_id" : ObjectId("59f24c0555ee5a5897e1b23e"),
    "user" : ObjectId("59f24b3a55ee5a5897e1b1ec"),
    "followers" : [
        ObjectId("59f24bda1d048d1edad4bda8")
    ]
}
{
    "_id" : ObjectId("59f24c8855ee5a5897e1b292"),
    "user" : ObjectId("59f24bda55ee5a5897e1b22c"),
    "followers" : [
        ObjectId("59f24bda1d048d1edad4bda8")
    ]
}
>

以下是我从Card模型中获得的所有内容:

> db.cards.find().pretty()
{
    "_id" : ObjectId("59f24bc01d048d1edad4bda6"),
    "title" : "A day or two with Hubtel's HTTP API",
    "content" : "a day or two",
    "external" : "",
    "slug" : "a-day-or-two-with-hubtels-http-api-df77056d",
    "createdBy" : "seanmavley",
    "createdById" : ObjectId("59f24b391d048d1edad4bda5"),
    "createdAt" : ISODate("2017-10-26T20:55:28.293Z"),
    "__v" : 0
}
{
    "_id" : ObjectId("59f24c5f1d048d1edad4bda9"),
    "title" : "US couple stole goods worth $1.2m from Amazon",
    "content" : "for what",
    "external" : "https://bbc.com",
    "slug" : "us-couple-stole-goods-worth-dollar12m-from-amazon-49b0a524",
    "createdBy" : "nkansahrexford",
    "createdById" : ObjectId("59f24bda1d048d1edad4bda8"),
    "createdAt" : ISODate("2017-10-26T20:58:07.793Z"),
    "__v" : 0
}

使用您的Populate Virtual示例(@Veeram),这是我得到的响应:

{"state":true,"msg":"Follow list","doc":{"_id":"59f24c0555ee5a5897e1b23d","user":"59f24bda1d048d1edad4bda8","following":["59f24b3a55ee5a5897e1b1ec","59f24bda55ee5a5897e1b22c"],"followers":[],"id":"59f24c0555ee5a5897e1b23d","followingCards":[]}}

该followingCards数组为空.

$lookup另一方面,使用查询只返回[]

我可能错过了什么？

Answer 1

您可以在聚合管道中使用虚拟填充或$lookup运算符。

使用虚拟填充

FollowSchema.virtual('followingCards', {
    ref: 'Card',
    localField: 'following',
    foreignField: 'createdById'
});

Follow.findOne({ 
   'user': Types.ObjectId(user_id) })
   .populate('followingCards')
   .exec(function(err, doc) {      
      console.log(JSON.stringify(doc));
});

使用$lookup聚合

Follow.aggregate([
  {
    "$match": {
      "user": Types.ObjectId(user_id) 
    }
  },
  {
    "$lookup": {
      "from": "cards",
      "localField": "following",
      "foreignField": "createdById",
      "as": "followingCards"
    }
  }
]).exec(function (err, doc) {
     console.log(JSON.stringify(doc));
})