从python列表中获取值序列

Question

我有这样的数组,

a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]

我想制作小于7的值列表(如下所示)

b = [[3,2,5],[4,5,6,3],[4,5],[5],[4],[6]]

所以我使用了以下方法,

>>> from itertools import takewhile
>>> a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]
>>>list(takewhile(lambda x: x < 7 , a))
[3, 2, 5]

但我只得到第一个序列.任何人都可以帮我解决这个问题吗？谢谢.

Answer 1

a = [3,2,5,7,4,5,6,3,8,4,5,7,8,9,5,7,8,4,9,7,6]
from itertools import groupby
[list(g) for k, g in groupby(a, lambda x:x<7) if k]

输出:

[[3, 2, 5], [4, 5, 6, 3], [4, 5], [5], [4], [6]]