React Native Invariant Violation:查看配置

Question

我正在尝试在React Native项目上使用不同的屏幕练习.这是我在App.js文件中的代码.

import React, { Component } from 'react';
import {
  Platform,
  StyleSheet,
  Text,
  View
} from 'react-native';

import { StackNavigator } from 'react-navigation';

class HomeScreen extends React.Component {
    static navigationOptions = {
        title: "welcome",
    };
    render() {
        return <Text style={{ color: 'black '}}>Hello, Navigation!</Text>;
    }
}

const navigation = StackNavigator({
    Home: { screen: HomeScreen },

});

export default class App extends Component<{}> {
  render() {
    return <navigation/>;
  }
}

const styles = StyleSheet.create({
  container: {
    flex: 1,
    justifyContent: 'center',
    alignItems: 'center',
    backgroundColor: '#fff',
  },
});

import React, { Component } from 'react';
import {
  Platform,
  StyleSheet,
  Text,
  View
} from 'react-native';

import { StackNavigator } from 'react-navigation';

class HomeScreen extends React.Component {
    static navigationOptions = {
        title: "welcome",
    };
    render() {
        return <Text style={{ color: 'black '}}>Hello, Navigation!</Text>;
    }
}

const navigation = StackNavigator({
    Home: { screen: HomeScreen },

});

export default class App extends Component<{}> {
  render() {
    return <navigation/>;
  }
}

const styles = StyleSheet.create({
  container: {
    flex: 1,
    justifyContent: 'center',
    alignItems: 'center',
    backgroundColor: '#fff',
  },
});

当我运行react-native run-android时,我得到一个Invariant Violation,告诉我"查看配置未找到或名称导航".然后是发生此违规行为的所有网站.请帮助谢谢

Answer 1

任何组件的名称必须大写.在您的名称中,组件"navigation"不是大写的.它应该是"导航".