如何将x-www-form-urlencoded字符串转换为JSON？

Question

application/x-www-form-urlencoded string的例子

CorrelationId=1&PickedNumbers%5B%5D=1&PickedNumbers%5B%5D=2&PickedNumbers%5B%5D=3&PickedNumbers%5B%5D=4

进入JSON

var gamePlayData = {
            CorrelationId: gameId,
            PickedNumbers: ["1","2","3","4"]
        };

Answer 1

如果您正在使用node或browserify,则可以使用qs.

var qs = require('qs')
var encodedString = "CorrelationId=1&PickedNumbers%5B%5D=1&PickedNumbers%5B%5D=2&PickedNumbers%5B%5D=3&PickedNumbers%5B%5D=4" 

console.log(qs.parse(encodedString))
// { CorrelationId: '1', PickedNumbers: [ '1', '2', '3', '4' ] }

Answer 2

我最近一直在处理这个:我必须解析可能包含嵌套最多5级深度的对象的数据.我需要代码能够处理相当复杂的数据,但不能解码URI这么简单id=213.

我花了很长时间在谷歌上,试图找到一个(半)优雅的解决方案,这个问题不断出现.因为它获得1个视图/天(给予或接受)我决定在这里发布我的解决方案,希望它可以帮助某人:

function form2Json(str)
{
    "use strict";
    var obj,i,pt,keys,j,ev;
    if (typeof form2Json.br !== 'function')
    {
        form2Json.br = function(repl)
        {
            if (repl.indexOf(']') !== -1)
            {
                return repl.replace(/\](.+?)(,|$)/g,function($1,$2,$3)
                {
                    return form2Json.br($2+'}'+$3);
                });
            }
            return repl;
        };
    }
    str = '{"'+(str.indexOf('%') !== -1 ? decodeURI(str) : str)+'"}';
    obj = str.replace(/\=/g,'":"').replace(/&/g,'","').replace(/\[/g,'":{"');
    obj = JSON.parse(obj.replace(/\](.+?)(,|$)/g,function($1,$2,$3){ return form2Json.br($2+'}'+$3);}));
    pt = ('&'+str).replace(/(\[|\]|\=)/g,'"$1"').replace(/\]"+/g,']').replace(/&([^\[\=]+?)(\[|\=)/g,'"&["$1]$2');
    pt = (pt + '"').replace(/^"&/,'').split('&');
    for (i=0;i<pt.length;i++)
    {
        ev = obj;
        keys = pt[i].match(/(?!:(\["))([^"]+?)(?=("\]))/g);
        for (j=0;j<keys.length;j++)
        {
            if (!ev.hasOwnProperty(keys[j]))
            {
                if (keys.length > (j + 1))
                {
                    ev[keys[j]] = {};
                }
                else
                {
                    ev[keys[j]] = pt[i].split('=')[1].replace(/"/g,'');
                    break;
                }
            }
            ev = ev[keys[j]];
        }
    }
    return obj;
}

我测试了它,数据如下面的字符串(4级深):

str  = "id=007&name[first]=james&name[last]=bond&name[title]=agent&personalia[occupation]=spy&personalia[strength]=women&personalia[weakness]=women&tools[weapons][close][silent]=garrot&tools[weapons][medium][silent]=pistol_supressed&tools[weapons][medium][loud]=smg&tools[weapons][far][silent]=sniper&tools[movement][slow]=foot&tools[movement][far]=DBS";

它整齐地返回一个对象,当传递JSON.stringify出来时,就像这样:

{"id":"007","name":{"title":"agent","first":"james","last":"bond"},"personalia":{"weakness":"women","occupation":"spy","strength":"women"},"tools":{"movement":{"far":"DBS","slow":"foot"},"weapons":{"close":{"silent":"garrot"},"medium":{"silent":"pistol_supressed","loud":"smg"},"far":{"silent":"sniper"}}}}

它传递一个的JSLint检查,忽略当空格,.和[^...]和接受++.总而言之,我认为这是可以接受的.

Answer 3

这是Node.js的核心模块现在:https://nodejs.org/api/querystring.html#querystring_querystring_parse_str_sep_eq_options

var qs = require('querystring')

var json = qs.parse('why=not&sad=salad')
    // { why: 'not', sad: 'salad' }

也适用于编码字符:

var json2 = qs.parse('http%3A%2F%2Fexample.com&sad=salad')
    // { url: 'http://example.com', sad: 'salad' }

Answer 4

以下代码应该做的伎俩:

var str = 'CorrelationId=1&PickedNumbers%5B%5D=1&PickedNumbers%5B%5D=2&PickedNumbers%5B%5D=3&PickedNumbers%5B%5D=4';
var keyValuePairs = str.split('&');
var json = {};
for(var i=0,len = keyValuePairs.length,tmp,key,value;i <len;i++) {
    tmp = keyValuePairs[i].split('=');
    key = decodeURIComponent(tmp[0]);
    value = decodeURIComponent(tmp[1]);
    if(key.search(/\[\]$/) != -1) {
        tmp = key.replace(/\[\]$/,'');
        json[tmp] = json[tmp] || [];
        json[tmp].push(value);
    }
    else {
        json[key] = value;
    }
}

Answer 5

试试这个->

// convert string to object
str = 'a=6&id=99';
var arr = str.split('&');
var obj = {};
for(var i = 0; i < arr.length; i++) {
    var bits = arr[i].split('=');
    obj[bits[0]] = bits[1];
}
//alert(obj.a);
//alert(obj.id);

// convert object back to string
str = '';
for(key in obj) {
    str += key + '=' + obj[key] + '&';
}
str = str.slice(0, str.length - 1); 
alert(str);

或者使用这个（JQuery）http://api.jquery.com/jQuery.param/