合并spannable对象时出错

Question

我想合并3个spannable对象.这段代码工作正常:

Spannable s1 = new SpannableStringBuilder("bold");
             s1.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), 0, s1.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
             Spannable s2 = new SpannableStringBuilder("not");
             Spannable s3 = new SpannableStringBuilder("BOLD");
             s3.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), 0, s3.length(), Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
             finishSpan = (Spanned) TextUtils.concat(s1,s2);
             finishSpan = (Spanned) TextUtils.concat(finishSpan,s3);

////////////////////////////////////////////////// ////

要么 finishSpan = (Spanned) TextUtils.concat(s1,s2,s3);

我有相同的代码但是当我合并3个对象时,结果是错误的.我已经检查过某些元素的类型是否正确.
beginningOfModifiedSpannable是粗体,selectionSpannable是正常的,endOfModifiedSpannable是粗体但是它们的合并是错误的.只有结果字符串的最后一部分是粗体.为什么会这样？我上面有相同的代码,效果很好!

  Spannable str = contentText.getText();
            Spannable selectionSpannable = new SpannableStringBuilder(str, selectionStart, selectionEnd);
            StyleSpan[] ss = selectionSpannable.getSpans(0, selectionSpannable.length(), StyleSpan.class);

            boolean exists = false;
            for (int i = 0; i < ss.length; i++) {
                if (ss[i].getStyle() == android.graphics.Typeface.BOLD){
                 selectionSpannable.removeSpan(ss[i]);
                    exists = true;
                }
            }

            if (!exists){
                str.setSpan(new StyleSpan(android.graphics.Typeface.BOLD), selectionStart, selectionEnd, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
            }
            else {

             Spannable endOfModifiedSpannable = new SpannableStringBuilder(str, selectionEnd, contentText.getText().length());
             Spannable beginningOfModifiedSpannable = new SpannableStringBuilder(str, 0, selectionStart);
             Spanned finishSpan = null;

             if(beginningOfModifiedSpannable.length() > 0) {

              if(endOfModifiedSpannable.length() > 0) {
               finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);
               finishSpan = (Spanned) TextUtils.concat(finishSpan,endOfModifiedSpannable);
                 }
              else {
               finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);
              }

             }
             else {
              if(endOfModifiedSpannable.length() > 0) {
               finishSpan = (Spanned) TextUtils.concat(selectionSpannable,endOfModifiedSpannable);
                     }
                  else {
                   finishSpan = selectionSpannable;
                  }
                 }
contentText.setText(finishSpan);

我再说一遍,我已经检查过3个部分是真的.例如,我有3个部分: Hel lo,wor ld

我注意到第一次合并是对的:

finishSpan = (Spanned) TextUtils.concat(beginningOfModifiedSpannable,selectionSpannable);

它看起来像Hel lo,wor

但第二个是错的

finishSpan = (Spanned) TextUtils.concat(finishSpan,endOfModifiedSpannable);

或者这种合并是错误的:

finishSpan = (Spanned) TextUtils.concat(finishSpan,selectionSpannable,endOfModifiedSpannable);

错误字符串的结果是:Hello,wo rld

但真正的结果必须是这样的:

Hel lo,世界

废话!

Answer 1

问题是你很可能对两个部分使用相同的CharacterStyle实例,第一个和第三个.每次向Spannable对象添加样式时,都需要使用新实例.

例如

    SpannableStringBuilder ssb = new SpannableStringBuilder("Hello,world");
    CharacterStyle c = new StyleSpan(Typeface.BOLD);
    ssb.setSpan(c, 0, 3, 0);
    ssb.setSpan(c, 9, 11, 0);

这将导致Hello,Wor ld

要获得正确的结果,您必须执行以下操作:

    SpannableStringBuilder ssb = new SpannableStringBuilder("Hello,world");
    CharacterStyle c = new StyleSpan(Typeface.BOLD);
    CharacterStyle c2 = new StyleSpan(Typeface.BOLD);
    ssb.setSpan(c, 0, 3, 0);
    ssb.setSpan(c2, 9, 11, 0);