这是我的对象:
var obj = {
"flag": false,
"text": "good text",
"someArray": [
{
"questionId": 11,
"text": "qwe",
"TypeId": "B",
"source": "oooooo"
},
{
"questionId": 12,
"text": "zxc",
"TypeId": "A",
"source": "pppppp"
},
{
"questionId": 13,
"text": "asd",
"TypeId": "D",
"source": "cccccc"
}
]
}
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我想要做的是从someArray属性TypeId和source. 我怎样才能用 lodash 做到这一点?我正在尝试使用 _.pick,但我不知道如何在里面使用它someArray。
您想使用 的反义词_.pick,即_.omit通过将它们映射到 返回没有给定属性的对象_.map
var obj = {
"flag": false,
"text": "good text",
"someArray": [{
"questionId": 11,
"text": "qwe",
"TypeId": "B",
"source": "oooooo"
}, {
"questionId": 12,
"text": "zxc",
"TypeId": "A",
"source": "pppppp"
}, {
"questionId": 13,
"text": "asd",
"TypeId": "D",
"source": "cccccc"
}]
}
obj.someArray = _.map(obj.someArray, o => _.omit(o, ['TypeId', 'source']));
console.log(obj)Run Code Online (Sandbox Code Playgroud)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>Run Code Online (Sandbox Code Playgroud)