the*_*der 13 javascript arrays grouping javascript-objects
我有一个像下面这样的对象数组.
{name: "Mc Donald", quantity: 4, maleCount: 1, femaleCount: 0}
{name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0}
{name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0}
{name: "Mc Donald", quantity: 4, maleCount: 0, femaleCount: 1}
{name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1}
{name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0}
{name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1}
{name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1}
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我想将它们分组并将其中的所有值相加.例如,决赛将是这样的:
{name: "Mc Donald", quantity: 8, maleCount: 1, femaleCount: 1}
{name: "KFC", quantity: 54, maleCount: 3, femaleCount: 3}
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我怎样才能在JavaScript中实现这一目标?
我试图在网上找到一些解决方案,但它不是我想要的.例如这个解决方案
Fal*_*aly 14
你可以使用array reduce:
var arr = [
{name: "Mc Donald", quantity: 4, maleCount: 1, femaleCount: 0},
{name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0},
{name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0},
{name: "Mc Donald", quantity: 4, maleCount: 0, femaleCount: 1},
{name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1},
{name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0},
{name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1},
{name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1}
];
var finalArr = arr.reduce((m, o) => {
var found = m.find(p => p.name === o.name);
if (found) {
found.quantity += o.quantity;
found.maleCount += o.maleCount;
found.femaleCount += o.femaleCount;
} else {
m.push(o);
}
return m;
}, []);
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您可以使用forEach()循环并添加到新数组.您可以将空对象作为thisArg参数传递,您可以this在回调函数中使用该参数,并且在第二个forEach上下文中this仍然会因为箭头函数而与第一个回调函数中的相同.
var data = [{"name":"Mc Donald","quantity":4,"maleCount":1,"femaleCount":0},{"name":"KFC","quantity":9,"maleCount":1,"femaleCount":0},{"name":"KFC","quantity":9,"maleCount":1,"femaleCount":0},{"name":"Mc Donald","quantity":4,"maleCount":0,"femaleCount":1},{"name":"KFC","quantity":9,"maleCount":0,"femaleCount":1},{"name":"KFC","quantity":9,"maleCount":1,"femaleCount":0},{"name":"KFC","quantity":9,"maleCount":0,"femaleCount":1},{"name":"KFC","quantity":9,"maleCount":0,"femaleCount":1}]
var result = [], keys = ['quantity', 'maleCount', 'femaleCount']
data.forEach(function(e) {
if(!this[e.name]) result.push(this[e.name] = e);
else keys.forEach(k => this[e.name][k] += e[k])
}, {})
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您可以使用哈希表进行分组,并使用数组作为具有变量值的键.
var array = [{ name: "Mc Donald", quantity: 4, maleCount: 1, femaleCount: 0 }, { name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0 }, { name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0 }, { name: "Mc Donald", quantity: 4, maleCount: 0, femaleCount: 1 }, { name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1 }, { name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0 }, { name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1 }, { name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1 }],
groups = Object.create(null),
result = array.reduce(function (r, o) {
var values = ['quantity', 'maleCount', 'femaleCount'];
if (!groups[o.name]) {
groups[o.name] = { name: o.name };
r.push(groups[o.name]);
values.forEach(function (k) { groups[o.name][k] = 0; });
}
values.forEach(function (k) { groups[o.name][k] += o[k]; });
return r;
}, []);
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使用linq.js
var array = [{ name: "Mc Donald", quantity: 4, maleCount: 1, femaleCount: 0 }, { name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0 }, { name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0 }, { name: "Mc Donald", quantity: 4, maleCount: 0, femaleCount: 1 }, { name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1 }, { name: "KFC", quantity: 9, maleCount: 1, femaleCount: 0 }, { name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1 }, { name: "KFC", quantity: 9, maleCount: 0, femaleCount: 1 }],
result = Enumerable.From(array)
.GroupBy(
"$.name",
null,
"{ name: $.Key, quantity: $$.Sum('$.quantity'), maleCount: $$.Sum('$.maleCount'), femaleCount: $$.Sum('$.femaleCount') }"
)
.ToArray();
console.log(result);Run Code Online (Sandbox Code Playgroud)
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<script src="https://cdnjs.cloudflare.com/ajax/libs/linq.js/2.2.0.2/linq.js"></script>Run Code Online (Sandbox Code Playgroud)