prz*_*ekk 2 python flask python-3.x flask-wtforms
我想生成带有复选框的文件列表。我尝试使用 FieldList 但它没有按我预期的那样工作。我得到的不是带有指定文件名的复选框,而是带有以包含 FieldList 对象的变量命名的标签的复选框。有什么办法可以解决吗?
应用程序.py:
from flask import Flask, render_template
from flask_bootstrap import Bootstrap
from flask_wtf import FlaskForm
from wtforms import BooleanField, FieldList, SubmitField
app = Flask(__name__)
app.config['SECRET_KEY'] = 'development'
Bootstrap(app)
filenames = ['1.jpg', '2.jpg', '3.jpg', '4.jpg']
class FileListForm(FlaskForm):
filename = FieldList(BooleanField(), 'Files')
submit = SubmitField('Submit')
@app.route('/')
def listfiles():
form = FileListForm()
for filename in filenames:
form.filename.append_entry(filename)
return render_template('index.html',
form=form)
if __name__ == '__main__':
app.run(debug=True, port=5001)
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模板/index.html
{% import "bootstrap/wtf.html" as wtf %}
{{ wtf.quick_form(form) }}
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包:
click==6.7
dominate==2.3.1
Flask==0.12.2
Flask-Bootstrap==3.3.7.1
Flask-WTF==0.14.2
itsdangerous==0.24
Jinja2==2.9.6
MarkupSafe==1.0
visitor==0.1.3
Werkzeug==0.12.2
WTForms==2.1
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根据文档,WTForms'FieldList不应与BooleanField:
注意:由于 HTML 发送值的方式的限制,
FieldList不能包含BooleanField或SubmitField实例。
(即使 HTML 输出看起来有效。)也就是说,您没有看到您期望看到的内容,因为append_entry的第一个参数接受表单输入的值,而不是其标签。
相反,我建议动态创建表单类:
filenames = ['1.jpg', '2.jpg', '3.jpg', '4.jpg']
class FileListFormBase(FlaskForm):
submit = SubmitField('Submit')
def file_list_form_builder(filenames):
class FileListForm(FileListFormBase):
pass
for (i, filename) in enumerate(filenames):
setattr(FileListForm, 'filename_%d' % i, BooleanField(label=filename))
return FileListForm()
@app.route('/')
def listfiles():
form = file_list_form_builder(filenames)
return render_template('index.html', form=form)
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注意:默认的 HTML 表示将在顶部有“提交”按钮,因为库按照定义的顺序呈现字段。WTForms 本身不支持排序,所以这对你来说可能是一个更好的解决方案,即使它不太优雅:
filenames = ['1.jpg', '2.jpg', '3.jpg', '4.jpg']
def file_list_form_builder(filenames):
class FileListForm(FlaskForm):
pass
for (i, filename) in enumerate(filenames):
setattr(FileListForm, 'filename_%d' % i, BooleanField(label=filename))
setattr(FileListForm, 'submit', SubmitField('Submit'))
return FileListForm()
@app.route('/')
def listfiles():
form = file_list_form_builder(filenames)
return render_template('index.html', form=form)
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