cod*_*eek 13 javascript google-chrome
我在chrome中打开应用程序时收到一个奇怪的警告.我不知道如何摆脱这个警告
[违规]为滚动阻止"鼠标滚轮"事件添加了非被动事件监听器.考虑将事件处理程序标记为"被动"以使页面更具响应性.
任何人都帮我把这件事说出来.谢谢你
有一个事件监听器API的更新.
简而言之:
document.addEventListener('touchstart', handler, true);
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成为这个:
document.addEventListener('touchstart', handler, {capture: true});
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因为在您的情况下,您将事件监听器附加到touchstart,它应该是这样的:
document.addEventListener('touchstart', handler, {passive: true});
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这样,您可以提前设置哪个确切事件以及是否支持被动接口:
var passiveEvent = false;
try {
var opts = Object.defineProperty({}, 'passive', {
get: function () {
passiveEvent = true;
}
});
window.addEventListener("test", null, opts);
} catch (e) { }
// in my case I need both passive and capture set to true, change as you need it.
passiveEvent = passiveEvent ? { capture: true, passive: true } : true;
//if you need to handle mouse wheel scroll
var supportedWheelEvent: string = "onwheel" in HTMLDivElement.prototype ? "wheel" :
document.onmousewheel !== undefined ? "mousewheel" : "DOMMouseScroll";
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并使用这样的:
elementRef.addEventListener("touchstart", handler, passiveEvent);
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有关被动事件侦听器的更多详细信息,请访问:https: //github.com/WICG/EventListenerOptions/blob/gh-pages/explainer.md
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