Dou*_*ger 47 python datetime intervals dataframe pandas
给定两个dataframes df_1和df_2如何加入他们的行列,使得datetime列df_1是介于两者之间start,并end 在数据帧df_2:
print df_1
timestamp A B
0 2016-05-14 10:54:33 0.020228 0.026572
1 2016-05-14 10:54:34 0.057780 0.175499
2 2016-05-14 10:54:35 0.098808 0.620986
3 2016-05-14 10:54:36 0.158789 1.014819
4 2016-05-14 10:54:39 0.038129 2.384590
print df_2
start end event
0 2016-05-14 10:54:31 2016-05-14 10:54:33 E1
1 2016-05-14 10:54:34 2016-05-14 10:54:37 E2
2 2016-05-14 10:54:38 2016-05-14 10:54:42 E3
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获取相应的event位置和df1.timestamp之间df_2.startdf2.end
timestamp A B event
0 2016-05-14 10:54:33 0.020228 0.026572 E1
1 2016-05-14 10:54:34 0.057780 0.175499 E2
2 2016-05-14 10:54:35 0.098808 0.620986 E2
3 2016-05-14 10:54:36 0.158789 1.014819 E2
4 2016-05-14 10:54:39 0.038129 2.384590 E3
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Flo*_*oor 34
一个简单的解决方案是interval index从start and end设置创建closed = both然后使用get_loc来获取事件即(希望所有日期时间都在时间戳dtype)
df_2.index = pd.IntervalIndex.from_arrays(df_2['start'],df_2['end'],closed='both')
df_1['event'] = df_1['timestamp'].apply(lambda x : df_2.iloc[df_2.index.get_loc(x)]['event'])
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输出:
timestamp A B event
0 2016-05-14 10:54:33 0.020228 0.026572 E1
1 2016-05-14 10:54:34 0.057780 0.175499 E2
2 2016-05-14 10:54:35 0.098808 0.620986 E2
3 2016-05-14 10:54:36 0.158789 1.014819 E2
4 2016-05-14 10:54:39 0.038129 2.384590 E3
cs9*_*s95 18
idx = pd.IntervalIndex.from_arrays(df_2['start'], df_2['end'], closed='both')
event = df_2.loc[idx.get_indexer(df_1.timestamp), 'event']
event
0 E1
1 E2
1 E2
1 E2
2 E3
Name: event, dtype: object
df_1['event'] = event.values
df_1
timestamp A B event
0 2016-05-14 10:54:33 0.020228 0.026572 E1
1 2016-05-14 10:54:34 0.057780 0.175499 E2
2 2016-05-14 10:54:35 0.098808 0.620986 E2
3 2016-05-14 10:54:36 0.158789 1.014819 E2
4 2016-05-14 10:54:39 0.038129 2.384590 E3
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参考:一个问题IntervalIndex.get_indexer.
chr*_*orn 10
您可以使用模块pandasql
import pandasql as ps
sqlcode = '''
select df_1.timestamp
,df_1.A
,df_1.B
,df_2.event
from df_1
inner join df_2
on d1.timestamp between df_2.start and df2.end
'''
newdf = ps.sqldf(sqlcode,locals())
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选项1
idx = pd.IntervalIndex.from_arrays(df_2['start'], df_2['end'], closed='both')
df_2.index=idx
df_1['event']=df_2.loc[df_1.timestamp,'event'].values
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选项2
df_2['timestamp']=df_2['end']
pd.merge_asof(df_1,df_2[['timestamp','event']],on='timestamp',direction ='forward',allow_exact_matches =True)
Out[405]:
timestamp A B event
0 2016-05-14 10:54:33 0.020228 0.026572 E1
1 2016-05-14 10:54:34 0.057780 0.175499 E2
2 2016-05-14 10:54:35 0.098808 0.620986 E2
3 2016-05-14 10:54:36 0.158789 1.014819 E2
4 2016-05-14 10:54:39 0.038129 2.384590 E3
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在此方法中,我们假设使用了 TimeStamp 对象。
df2 start end event
0 2016-05-14 10:54:31 2016-05-14 10:54:33 E1
1 2016-05-14 10:54:34 2016-05-14 10:54:37 E2
2 2016-05-14 10:54:38 2016-05-14 10:54:42 E3
event_num = len(df2.event)
def get_event(t):
event_idx = ((t >= df2.start) & (t <= df2.end)).dot(np.arange(event_num))
return df2.event[event_idx]
df1["event"] = df1.timestamp.transform(get_event)
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的解释 get_event
对于 中的每个时间戳df1,比如说t0 = 2016-05-14 10:54:33,
(t0 >= df2.start) & (t0 <= df2.end)将包含 1 个 true。(参见示例 1)。然后,取一个点积 withnp.arange(event_num)得到 at0所属事件的索引。
例子:
示例 1
t0 >= df2.start t0 <= df2.end After & np.arange(3)
0 True True -> T 0 event_idx
1 False True -> F 1 -> 0
2 False True -> F 2
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以t2 = 2016-05-14 10:54:35另一个例子
t2 >= df2.start t2 <= df2.end After & np.arange(3)
0 True False -> F 0 event_idx
1 True True -> T 1 -> 1
2 False True -> F 2
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我们最终使用transform将每个时间戳转换为一个事件。
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