使用javascript或jquery删除url参数

Question

我正在尝试使用youtube数据api生成视频播放列表.但是,视频网址需要youtube.com/watch?v=3sZOD3xKL0Y格式,但api生成的是youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata.所以我需要做的是能够选择&符号之后的所有内容并将其从url中删除.使用javascript和某种正则表达式的任何方式吗？

Answer 1

我错过了什么？

为什么不:

url.split('?')[0] 

Answer 2

简单:

var new_url = old_url.substring(0, old_url.indexOf('?'));

修改:这将从url中删除所有参数或片段

var oldURL = [YOUR_URL_TO_REMOVE_PARAMS]
var index = 0;
var newURL = oldURL;
index = oldURL.indexOf('?');
if(index == -1){
    index = oldURL.indexOf('#');
}
if(index != -1){
    newURL = oldURL.substring(0, index);
}

Answer 3

嗯......寻找更好的方式......在这里

var onlyUrl = window.location.href.replace(window.location.search,'');

Answer 4

示例: http ://jsfiddle.net/SjrqF/

var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';

url = url.slice( 0, url.indexOf('&') );

要么:

示例: http ://jsfiddle.net/SjrqF/1/

var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';

url = url.split( '&' )[0];

Answer 5

使用这个功能：

var getCleanUrl = function(url) {
  return url.replace(/#.*$/, '').replace(/\?.*$/, '');
};

// get rid of hash and params
console.log(getCleanUrl('https://sidanmor.com/?firstname=idan&lastname=mor'));

如果您想要所有 href 部分，请使用以下命令：

var url = document.createElement('a');
url.href = 'https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container';

console.log(url.href); // https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container
console.log(url.protocol); // https:
console.log(url.host); // developer.mozilla.org
console.log(url.hostname); // developer.mozilla.org
console.log(url.port); // (blank - https assumes port 443)
console.log(url.pathname); // /en-US/search
console.log(url.search); // ?q=URL
console.log(url.hash); // #search-results-close-container
console.log(url.origin); // https://developer.mozilla.org

Answer 6

//user113716 code is working but i altered as below. it will work if your URL contain "?" mark or not
//replace URL in browser
if(window.location.href.indexOf("?") > -1) {
    var newUrl = refineUrl();
    window.history.pushState("object or string", "Title", "/"+newUrl );
}

function refineUrl()
{
    //get full url
    var url = window.location.href;
    //get url after/  
    var value = url = url.slice( 0, url.indexOf('?') );
    //get the part after before ?
    value  = value.replace('@System.Web.Configuration.WebConfigurationManager.AppSettings["BaseURL"]','');  
    return value;     
}

Answer 7

这对我有用：

window.location.replace(window.location.pathname)