Eri*_*ert 8

该操作似乎是组合map(aka Select)和reduce(aka Aggregate)操作的弱版本,仅限于二进制操作.我们可以做得更好!

public static IEnumerable<R> MyAggregate<T, R>(
  this IEnumerable<T> items,
  R seed,
  Func<T, R, R> mapper) 
{
  R current = seed;      
  foreach(T item in items)
  {
    current = mapper(item, current);
    yield return current;
  }
}
Run Code Online (Sandbox Code Playgroud)

现在你想要的功能只是一个特例:

static IEnumerable<int> PartialSum(this IEnumerable<int> items) =>
  items.MyAggregate(0, (i, s) => s + i); 
Run Code Online (Sandbox Code Playgroud)

评论者Tom Blodget指出,这要求总和操作具有一定的身份; 怎么没有呢?在这种情况下,您必须放弃使sum类型与summand类型不同的能力:

public static IEnumerable<T> PartialSum<T>(
  this IEnumerable<T> items,
  Func<T, T, T> sum)
{
  bool first = true;
  T current = default(T);
  foreach(T item in items) 
  {
    current = first ? item : sum(current, item);
    first = false;
    yield return current;
  }
}
Run Code Online (Sandbox Code Playgroud)

你可以使用它

myints.PartialSum((i, s) => i + s);
Run Code Online (Sandbox Code Playgroud)