Row*_*haw 5 t-sql for-xml common-table-expression sql-server-2008
我正在尝试生成一些具有不同嵌套级别的 XML,并且冒着过度简化的风险,输出 XML 将采用松散的格式:
<invoice number="1">
<charge code="foo" rate="123.00">
<surcharge amount="10%" />
</charge>
<charge code="bar" />
</invoice>
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我为此继承的数据库模式恰好将费用存储在不同的表中,这意味着附加费根据费用来源的表以不同的方式存储。
鉴于您不能将s 与 一起使用UNIONFOR XML,我UNION在 CTE 中做了一些 ing,因此大致如下:
WITH Charges ( [@code], [@rate], surcharge, InvoiceId ) AS (
SELECT code AS [@Code], amount AS [@rate], NULL as surcharge, InvoiceId
FROM item.charges
UNION ALL
SELECT
code AS [@Code],
amount AS [@rate],
(
SELECT amount AS [@amount]
FROM order.surcharges os
WHERE oc.ChargeId = os.ChargeId
FOR XML PATH('surcharge'), TYPE
),
InvoiceId
FROM order.charges oc
)
SELECT
Number AS [@number],
(
SELECT
[@code],
[@rate],
surcharge
FROM Charges
WHERE Charges.InvoiceId = i.InvoiceId
)
FROM Invoices i
FOR XML PATH( 'invoice' ), TYPE
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现在,这非常接近,给出(注意嵌套<surcharge>):
<invoice number="1">
<charge code="foo" rate="123.00">
<surcharge>
<surcharge amount="10%" />
</surcharge>
</charge>
<charge code="bar" />
</invoice>
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但我需要找到一种方法,使最终查询包含 XML 列的值,并将其视为元素的内容,而不是新元素。这是可能的,还是我需要采取新的方法?
看来,将(假)列命名为“*”将使用该列的内容作为元素的内容,因此按如下方式更改 SQL 使其可以工作:
WITH Charges ( [@code], [@rate], surcharge, InvoiceId ) AS (
SELECT code AS [@Code], amount AS [@rate], NULL as surcharge, InvoiceId
FROM item.charges
UNION ALL
SELECT
code AS [@Code],
amount AS [@rate],
(
SELECT amount AS [@amount]
FROM order.surcharges os
WHERE oc.ChargeId = os.ChargeId
FOR XML PATH('surcharge'), TYPE
),
InvoiceId
FROM order.charges oc
)
SELECT
Number AS [@number],
(
SELECT
[@code],
[@rate],
surcharge AS [*] -- Thsi will embed the contents of the previously generated XML in here.
FROM Charges
WHERE Charges.InvoiceId = i.InvoiceId
)
FROM Invoices i
FOR XML PATH( 'invoice' ), TYPE
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