使用like和wildcard过滤集合

Question

我需要获取以所需字母开头的所有文件,我正在尝试使用->where过滤器添加'like'为运算符但通配符不起作用.

        $files = File::files(storage_path($id_files));
        $files = collect($files);
        $files->transform(function ($item, $key){
            $item->public_filename = $item->getFilename();
            return $item;
        });

这是我们的目标数据,我需要创建一个public_filename应用过滤器的字段.我们的文件(dd($files)):

   Collection {#503 ?
  #items: array:3 [?
    0 => SplFileInfo {#525 ?
      -relativePath: ""
      -relativePathname: "atxt.txt"
      path: "/home/vagrant/Code/project/storage/app/uploads/general"
      filename: "atxt.txt"
      basename: "atxt.txt"
      pathname: "/home/vagrant/Code/project/storage/app/uploads/general/atxt.txt"
      extension: "txt"
      realPath: "/home/vagrant/Code/project/storage/app/uploads/general/atxt.txt"
      aTime: 2017-09-29 09:51:17
      mTime: 2017-09-27 14:39:11
      cTime: 2017-09-27 14:39:11
      inode: 32833
      size: 3
      perms: 0100777
      owner: 1000
      group: 1000
      type: "file"
      writable: true
      readable: true
      executable: true
      file: true
      dir: false
      link: false
    }
    1 => SplFileInfo {#524 ?
      -relativePath: ""
      -relativePathname: "batxt.txt"
      path: "/home/vagrant/Code/project/storage/app/uploads/general"
      filename: "batxt.txt"
      basename: "batxt.txt"
      pathname: "/home/vagrant/Code/project/storage/app/uploads/general/batxt.txt"
      extension: "txt"
      realPath: "/home/vagrant/Code/project/storage/app/uploads/general/batxt.txt"
      aTime: 2017-09-29 09:51:31
      mTime: 2017-09-27 14:39:11
      cTime: 2017-09-27 14:39:11
      inode: 32834
      size: 3
      perms: 0100777
      owner: 1000
      group: 1000
      type: "file"
      writable: true
      readable: true
      executable: true
      file: true
      dir: false
      link: false
    }
    2 => SplFileInfo {#526 ?
      -relativePath: ""
      -relativePathname: "txt.txt"
      path: "/home/vagrant/Code/project/storage/app/uploads/general"
      filename: "txt.txt"
      basename: "txt.txt"
      pathname: "/home/vagrant/Code/project/storage/app/uploads/general/txt.txt"
      extension: "txt"
      realPath: "/home/vagrant/Code/project/storage/app/uploads/general/txt.txt"
      aTime: 2017-09-27 14:39:11
      mTime: 2017-09-27 14:39:11
      cTime: 2017-09-27 14:39:11
      inode: 5438
      size: 3
      perms: 0100777
      owner: 1000
      group: 1000
      type: "file"
      writable: true
      readable: true
      executable: true
      file: true
      dir: false
      link: false
    }
  ]
}

我在尝试什么:

dd($files->where('public_filename','like','t%')); // 0 results

dd($files->where('public_filename','like','txt.txt')); //If I ommit wildcard and look for full name it retrieves correct file

所以我们的目标是:

dd($files->where('public_filename','like','t%')); // 1 result

任何的想法？我们可以使用通配符来使用like运算符来过滤集合吗？感谢你们!

Answer 1

确实where likelaravel集合中没有,但因为where函数也在后台使用过滤器,如评论中所述,您可以根据需要构建过滤器.

以下示例是过滤器返回名称以T开头的用户

    $collect = User::all()->filter(function($user){
        return starts_with($user->name, 'T');
    });

Laravel还有几个函数可以帮助操作和使用字符串,如ends_with(),str_contains()等.其他php字符串操作函数可以帮助你.

PS通常你会想要提取数据库来获取数据时进行过滤(至少我刚给出的例子)