我想创建一个接收DataFiles List的方法,然后在其中一个字段上使用String谓词过滤它,并返回DataFiles的List而不是字符串.
这是我的代码:
public static List<DataFile> someMethod(List<DataFile> dataFiles) {
return dataFiles
.stream()
.map(DataFile::getFileName)
.filter(companyAndDateFilter(date, BLABLA, LALALA))
.collect(Collectors.toList());
}
private static Predicate<String> companyAndDateFilter(LocalDate date, String... companyNames) {
String companies = getCompaniesAsString(companyNames);
String formattedDate = formatTheDate(date);
Pattern pattern = Pattern
.compile("^(" + companies + ")_(" + formattedDate + ")");
LOGGER.info("Filtering files using RegEx: " + pattern.pattern());
return pattern.asPredicate();
}
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当我这样做时,.map(DataFile::getFileName)我将我的流转换为,Stream<String>但我想保留它,Stream<DataFile>并仍然使用过滤器(即Predicate<String>)DataFile::getFileName.那可能吗?
public static List<DataFile> someMethod(List<DataFile> dataFiles) {
Predicate<String> hasCompanyAndDate = companyAndDateFilter(date, BLABLA, LALALA);
return dataFiles.stream()
.filter(dataFile -> hasCompanyAndDate.test(dataFile.getFileName()))
.collect(Collectors.toList());
}
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