Javascript 按键值对对象数组进行排序

Question

我试图对包含具有“在线”、“离线”、“忙碌”状态键的对象数组进行排序，因此只想以所有“在线”都出现在顶部的方式对数组进行排序，然后是“忙碌” ”然后“离线”

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];

arr.sort(function(first, second) {
   if (second.status == "online") return 1;

 });

console.log(arr);

这只会返回我的状态：顶部的“在线”。谢谢

Answer 1

尝试这个：

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];
           
 var statusOrder = ["online", "busy", "offline"];
 
 arr = arr.sort(function(a, b) { 
     return statusOrder.indexOf(a.status) - statusOrder.indexOf(b.status);
 });

 console.log(arr);

使用 ECMAScript6 甚至更短：

var arr = [{_id: "58e21249", name: "test2", status: "offline"},
           {_id: "58e1249", name: "test3", status: "online"},
           {_id: "58qwe49", name: "test21", status: "offline"},
           {_id: "58ed49", name: "test212", status: "online"},
           {_id: "58ee49", name: "test23", status: "offline"},
           {_id: "58xe49", name: "test12", status: "online"},
           {_id: "5849", name: "test2323", status: "busy"},
           {_id: "58er49", name: "test2121", status: "busy"}];
           
 var statusOrder = ["online", "busy", "offline"];
 
 arr = arr.sort((a, b) => statusOrder.indexOf(a.status) - statusOrder.indexOf(b.status));

 console.log(arr);