没有身体在PHP卷曲

Question

在这个代码片段中我想将$ jsonArray卷曲到url并得到必须是代码的响应体但我的问题是它给我的唯一的东西是1(真)

$array = [
    "type"=>"send",
    "phone"=>"989107786584"
];
$jsonArray = json_encode($array);
$curl = curl_init();
curl_setopt($curl,CURLOPT_URL,'http://79.175.166.98/chargebazi/otp.php');
curl_setopt($curl,CURLOPT_POST,$jsonArray);
$result = curl_exec($curl);
$responseCode = json_decode($result);
echo $responseCode;

Answer 1

添加选项CURLOPT_RETURNTRANSFER:

curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);

并在$result = curl_exec($curl);添加此块之后:

if ($result === false) {
    throw new \RuntimeException(curl_error($curl));
}

这样你就能看到错误.