使用RowCommand事件在GridView编辑上单击弹出引导模型

Question

我有一个Bootstrap模型弹出窗口:

<asp:UpdatePanel ID="upModal" runat="server">
<ContentTemplate>

<!-- Bootstrap Modal Dialog -->
<div class="modal fade" id="myModal" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
    <div class="modal-dialog">
        <div class="modal-content">
            <div class="modal-header">
                <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button>
                <h4 class="modal-title">ADD NEW BANQUET</h4>
            </div>
            <div class="modal-body" style="padding-left: 0px;padding-right:0px">
              <div class="col-lg-12" style="padding-left: 0px;padding-right:0px">
                  <div class="form-group col-lg-6">
                    <label>Banquet ID:</label>
                    <u><asp:Label ID="lblID" CssClass="form-control" Text="AUTO ID" runat="server"></asp:Label></u>
                  </div>
                  <div class="form-group col-lg-6">
                    <label>Banquet Name:</label>
                    <asp:TextBox ID="txtName" CssClass="form-control" runat="server"></asp:TextBox>
                  </div>
              </div>

            <div class="modal-footer" style="padding-left: 0px;padding-right:0px">
              <asp:Button ID="btnSave" runat="server" OnClick="btnSave_Click" 
                  CssClass="btn btn-success btn-lg btn-block" Text="SAVE" UseSubmitBehavior="false"
                  data-dismiss="modal" />
                </div>
            </div>
          </div>
    </div>
</div>
<!-- /.modal -->

</ContentTemplate>
</asp:UpdatePanel>
<!-- /.upModel -->

而GridView是:

<div class="col-lg-12 table-responsive">
    <asp:GridView ID="gvBanquet" CssClass="table table-striped table-bordered table-hover" runat="server" 
        AutoGenerateColumns="false" OnRowCommand="gvBanquet_RowCommand" AllowPaging="True" PageSize="5" 
        EmptyDataText="No record found!" OnPageIndexChanging="gvBanquet_PageIndexChanging" ShowHeaderWhenEmpty="true">
        <Columns>
            <asp:TemplateField HeaderText="Banquet Name">
                <ItemTemplate>
                    <asp:Label ID="lblID" runat="server" Visible="false" Text='<% #Eval("bqtID") %>'></asp:Label>
                    <asp:Label ID="lblName" runat="server" Text='<% #Eval("bqtName") %>' ></asp:Label>
                </ItemTemplate>
            </asp:TemplateField>

            <asp:TemplateField>
                <HeaderTemplate>
                    <center>Events</center>
                </HeaderTemplate>
                <ItemTemplate>
                    <asp:Button ID="btnEdiit" runat="server" CssClass="btn btn-danger btn-sm" CommandName="EditRow" Text="Edit" />
                </ItemTemplate>
            </asp:TemplateField>
        </Columns>
        <HeaderStyle BackColor="#5cb85c" BorderColor="#4CAE4C" ForeColor="White"></HeaderStyle>
        <PagerStyle Font-Size="Larger" ForeColor="Black" HorizontalAlign="Center" />
    </asp:GridView>
</div>
<!-- /.col-lg-12 -->

这是RowCommand事件:

protected void gvBanquet_RowCommand(object sender, GridViewCommandEventArgs e)
{
    GridViewRow row = (GridViewRow)(((Control)e.CommandSource).NamingContainer);
    int index = row.RowIndex;

    string id = GetTextFromGridViewLabel(gvBanquet,index,"lblID");
    string name = GetTextFromGridViewLabel(gvBanquet, index, "lblName");

    switch (e.CommandName)
    {
        case "EditRow":
            lblID.Text = id;
            txtName.Text = name;
            break;
        default:
            break;
    }
}

我的问题是当我点击GridView中的编辑按钮时,Bootstrap模型没有弹出GridView行id和name从GridView行弹出.

Answer 1

这可以是一个解决方案,并遵循以下步骤:

• 在另一个UpdatePanel中添加GridView.

• RowCommand在第一个UpdatePanel中触发GridView 事件,upModel如:

  <ContentTemplate>
  <Triggers>
      <asp:AsyncPostBackTrigger ControlID="gvBanquet"  EventName="RowCommand" />  
  </Triggers>
  

• 最后StringBuilder在RowCommand事件中运行以下代码:

  case "EditRow":
      lblID.Text = id;
      txtName.Text = name;
  
      System.Text.StringBuilder sb = new System.Text.StringBuilder();
      sb.Append(@"<script type='text/javascript'>");
      sb.Append("$('#myModal').modal('show');");
      sb.Append(@"</script>");
      ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "MyModal", 
      sb.ToString(), false);
  
      break;
  

它会在编辑点击时显示弹出窗口: