Vik*_*k G 2 sql postgresql select subquery where-clause
records Year | Dept | Expense | Month因此,每年/每个部门最多可以有一个记录.
我有一个子查询,它根据约束返回下面的数据.
Year | Dept
2001 | HR
2001 | ACC
2001 | TECH
2002 | TECH
2003 | HOUSE-KEEPING
2003 | TECH
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现在,我需要在同一个表上运行另一个查询,以获得每个值对的总计费用.
使用子查询的输出,我的主要查询将是类似的
select Dept, sum(Expense)
from records
where (Year, Dept) in (...)
... I want to iterate over value pairs from the subquery
(SUBQUERY which returns
Year | Dept
2001 | HR
2001 | ACC
2002 | TECH
2003 | HOUSE-KEEPING
)
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当我运行这个select语句时,返回的输出仅包含三年内TECH的数据.
请帮助理解我如何在子查询的所有行上运行主选择
将子查询重构为连接.
说你有
SELECT a, b FROM t1 WHERE (x,y) IN (SELECT x1, y1 FROM t2 WHERE ...)
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哪个不行.你重写了
SELECT a, b
FROM t1
INNER JOIN (
-- subquery here:
SELECT x1, y1
FROM t2
WHERE ...
) AS some_alias
WHERE t1.x = some_alias.x1
AND t1.y = some_alias.y1;
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请注意,在PostgreSQL中,您不应该使用CTE(WITH查询).
你可以缩写
WHERE t1.x = some_alias.x1
AND t1.y = some_alias.y1;
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至
WHERE (x, y) = (x1, y1)
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虽然.
在这里找到解决方案:
SELECT dept, SUM(expense) FROM records
WHERE ROW(year, dept) IN (SELECT x, y FROM otherTable)
GROUP BY dept;
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ROW函数发挥了神奇作用。
现在到 2022 年,您可以直接执行以下操作:
SELECT dept, SUM(expense) FROM records
WHERE (year, dept) IN (SELECT year, dept FROM otherTable);
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