lee*_*wah 4 mysql scala apache-spark apache-spark-sql spark-dataframe
在MySQL中,我可以这样查询:
select
cast(from_unixtime(t.time, '%Y-%m-%d %H:00') as datetime) as timeHour
, ...
from
some_table t
group by
timeHour, ...
order by
timeHour, ...
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其中timeHour
在GROUP BY
为一个选择的表达的结果。
但是我只是尝试了一个类似于中的查询Sqark SQL
,但出现了错误
Error: org.apache.spark.sql.AnalysisException:
cannot resolve '`timeHour`' given input columns: ...
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我的查询Spark SQL
是这样的:
select
cast(t.unixTime as timestamp) as timeHour
, ...
from
another_table as t
group by
timeHour, ...
order by
timeHour, ...
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这种结构可能Spark SQL
吗?
Spark SQL中可以使用这种构造吗?
是的,是。您可以通过两种方式使其在Spark SQL中运行,以在GROUP BY
和ORDER BY
子句中使用新列
使用子查询的方法1:
SELECT timeHour, someThing FROM (SELECT
from_unixtime((starttime/1000)) AS timeHour
, sum(...) AS someThing
, starttime
FROM
some_table)
WHERE
starttime >= 1000*unix_timestamp('2017-09-16 00:00:00')
AND starttime <= 1000*unix_timestamp('2017-09-16 04:00:00')
GROUP BY
timeHour
ORDER BY
timeHour
LIMIT 10;
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方法2使用WITH //优雅的方式:
-- create alias
WITH table_aliase AS(SELECT
from_unixtime((starttime/1000)) AS timeHour
, sum(...) AS someThing
, starttime
FROM
some_table)
-- use the same alias as table
SELECT timeHour, someThing FROM table_aliase
WHERE
starttime >= 1000*unix_timestamp('2017-09-16 00:00:00')
AND starttime <= 1000*unix_timestamp('2017-09-16 04:00:00')
GROUP BY
timeHour
ORDER BY
timeHour
LIMIT 10;
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在Scala中使用Spark DataFrame(wo SQL)API的替代方法:
// This code may need additional import to work well
val df = .... //load the actual table as df
import org.apache.spark.sql.functions._
df.withColumn("timeHour", from_unixtime($"starttime"/1000))
.groupBy($"timeHour")
.agg(sum("...").as("someThing"))
.orderBy($"timeHour")
.show()
//another way - as per eliasah comment
df.groupBy(from_unixtime($"starttime"/1000).as("timeHour"))
.agg(sum("...").as("someThing"))
.orderBy($"timeHour")
.show()
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