Ale*_*lex 2 python regex os.walk
我想获得一个适用于我所拥有的正则表达式的文件列表.我想我应该使用os.walk,但我如何使用正则表达式?
谢谢.
我不知道stdlib实现这一点的任何东西,但代码并不难:
import os, os.path
def iter_matching(dirpath, regexp):
"""Generator yielding all files under `dirpath` whose absolute path
matches the regular expression `regexp`.
Usage:
>>> for filename in iter_matching('/', r'/home.*\.bak'):
.... # do something
"""
for dir_, dirnames, filenames in os.walk(dirpath):
for filename in filenames:
abspath = os.path.join(dir_, filename)
if regexp.match(abspath):
yield abspath
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或者更一般:
import os, os.path
def filter_filenames(dirpath, predicate):
"""Usage:
>>> for filename in filter_filenames('/', re.compile(r'/home.*\.bak').match):
.... # do something
"""
for dir_, dirnames, filenames in os.walk(dirpath):
for filename in filenames:
abspath = os.path.join(dir_, filename)
if predicate(abspath):
yield abspath
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如果您的正则表达式可以转换为 shell 表达式,例如foo/*.txt您可以使用glob.
>>> import glob
>>> glob.glob('./[0-9].*')
['./1.gif', './2.txt']
>>> glob.glob('*.gif')
['1.gif', 'card.gif']
>>> glob.glob('?.gif')
['1.gif']
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