yav*_*ava 40 java http http-status-code-403
当我从具有403响应的URL获取数据时
is = conn.getInputStream();
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它抛出IOException,我无法获取响应数据.
但是当我使用firefox并直接访问该URL时,ResponseCode仍然是403,但我可以获得html内容
coo*_*ird 66
根据javadocs,该HttpURLConnection.getErrorStream方法将返回一个InputStream可用于从错误条件(例如404)中检索数据的方法.
qwe*_*guy 20
用法示例HttpURLConnection:
String response = null;
try {
URL url = new URL("http://google.com/pagedoesnotexist");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
// Hack to force HttpURLConnection to run the request
// Otherwise getErrorStream always returns null
connection.getResponseCode();
InputStream stream = connection.getErrorStream();
if (stream == null) {
stream = connection.getInputStream();
}
// This is a try with resources, Java 7+ only
// If you use Java 6 or less, use a finally block instead
try (Scanner scanner = new Scanner(stream)) {
scanner.useDelimiter("\\Z");
response = scanner.next();
}
} catch (MalformedURLException e) {
// Replace this with your exception handling
e.printStackTrace();
} catch (IOException e) {
// Replace this with your exception handling
e.printStackTrace();
}
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Inf*_*ity 13
尝试这样的事情:
try {
String text = "url";
URL url = new URL(text);
URLConnection conn = url.openConnection();
// fake request coming from browser
conn.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows; U; Windows NT 6.1; en-GB; rv:1.9.2.13) Gecko/20101203 Firefox/3.6.13 (.NET CLR 3.5.30729)");
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream(), "UTF-8"));
String f = in.readLine();
in.close();
System.out.println(f);
} catch (Exception e) {
e.printStackTrace();
}
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小智 5
尝试这个:
BufferedReader reader = new BufferedReader(new InputStreamReader(con.getResponseCode() / 100 == 2 ? con.getInputStream() : con.getErrorStream()));
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