在Python中从FTP文件夹获取最新文件(文件名包含空格)

Man*_*ani 7 python ftplib python-2.7

我有一个要求,我必须从FTP文件夹中提取最新的文件,问题是文件名有空格,文件名具有特定的模式.以下是我实施的代码:

import sys
from ftplib import FTP
import os
import socket
import time
import pandas as pd
import numpy as np
from glob import glob
import datetime as dt
from __future__ import with_statement

ftp = FTP('')
ftp.login('','')
ftp.cwd('')
ftp.retrlines('LIST')

filematch='*Elig.xlsx'
downloaded = []

for filename in ftp.nlst(filematch):
  fhandle=open(filename, 'wb')
  print 'Getting ' + filename
  ftp.retrbinary('RETR '+ filename, fhandle.write)
  fhandle.close()
  downloaded.append(filename)

ftp.quit()
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我知道我可以在ftp.dir()命令中添加一个空列表,但由于文件名有空格,我无法以正确的方式拆分它并选择我上面提到的类型的最新文件.

任何帮助都会很棒.

Ric*_*ann 5

如果 FTP 服务器支持,您可以通过发送MDTM命令来获取文件 mtime,并相应地对 FTP 服务器上的文件进行排序。

def get_newest_files(ftp, limit=None):
    """Retrieves newest files from the FTP connection.

    :ftp: The FTP connection to use.
    :limit: Abort after yielding this amount of files.
    """

    files = []

    # Decorate files with mtime.
    for filename in ftp.nlst():
        response = ftp.sendcmd('MDTM {}'.format(filename))
        _, mtime = response.split()
        files.append((mtime, filename))

    # Sort files by mtime and break after limit is reached.
    for index, decorated_filename in enumerate(sorted(files, reverse=True)):
        if limit is not None and index >= limit:
            break

        _, filename = decorated_filename  # Undecorate
        yield filename


downloaded = []

# Retrieves the newest file from the FTP server.
for filename in get_newest_files(ftp, limit=1):
    print 'Getting ' + filename

    with open(filename, 'wb') as file:
        ftp.retrbinary('RETR '+ filename, file.write)

    downloaded.append(filename)
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