C ++中动态分配的输入和输出二维数组

Question

我的目标是动态分配二维数组，以便它提示用户输入他们要创建的矩阵数组的行和列的大小。在动态分配行和列的大小之后，用户将输入所需的值。以下是我的C ++代码：

#include <iostream>
using namespace std;

int main()
{

int* x = NULL;
int* y = NULL;
int numbers, row, col;
cout << "Please input the size of your rows: " << endl;
std::cin >> row;
cout << "Please input the size of your columns: " << endl;
std::cin >> col;
x = new int[row]; 
y = new int[col];
cout << "Please input your array values: " << endl;
for (int i = 0; i<row; i++)
{
    for (int j = 0; j<col; i++)
    {
        std::cin >> numbers; 
        x[i][j] = numbers;
    }
}

cout << "The following is your matrix: " << endl;
for (int i = 0; i < row; i++)
{
    for (int j = 0; j<col; j++)
    {
        std::cout << "[" << i << "][" <<j << "] = " << x[i][j] << std::endl;
    }
}

delete[] x;
delete[] y;
system("pause");
return 0;
}

不幸的是，当我在Visual Studios上运行此代码时，它给了我编译错误。

Answer 1

这是使用c ++ 11 new和delete运算符动态分配2D数组（10行20列）的方法

码：

int main()
{

//Creation
int** a = new int*[10]; // Rows

for (int i = 0; i < 10; i++)
{
    a[i] = new int[20]; // Columns
}

//Now you can access the 2D array 'a' like this a[x][y]

//Destruction
for (int i = 0; i < 10; i++)
{
    delete[] a[i]; // Delete columns
}
delete[] a; // Delete Rows
return 0;
}