Kal*_*hal 3 python merge list dataframe pandas
我有一个看起来像的数据框
*id*, *name*, *URL*, *Type*
2, birth_france_by_region, http://abc. com, T1
2, birth_france_by_region, http://pt. python, T2
3, long_lat, http://abc. com, T3
3, long_lat, http://pqur. com, T1
4, random_time_series, http://sadsdc. com, T2
4, random_time_series, http://sadcadf. com, T3
5, birth_names, http://google. com, T1
5, birth_names, http://helloworld. com,T2
5, birth_names, http://hu. com, T3
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我想要一个此数据帧合并id相等的行,并具有对应于URL的Type列表, 所以最终输出应类似于
*id*, *name*, *URL*, *Type*
2,birth_france_by_region, [http://abc .com,http://pt.python], [T1,T2]
3,long_lat, [http://abc .com,http://pqur. com], [T3,T1]
4,random_time_series, [http://sadsdc. com,http://sadcadf .com,],[T2,T3]
5,birth_names, [http://google .com,http://helloworld. com,
http://hu. com] , [T1,T2,T3]
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我认为您需要groupby汇总tuple,然后转换为list:
df = df.groupby(['id','name']).agg(lambda x: tuple(x)).applymap(list).reset_index()
print (df)
id name \
0 2 birth_france_by_region
1 3 long_lat
2 4 random_time_series
3 5 birth_names
URL Type
0 [http://abc.cm, http://pt.python] [T1, T2]
1 [http://abc.cm, http://pqur.com] [T3, T1]
2 [http://sadsdc.com, http://sadcadf.com] [T2, T3]
3 [http://google.;com, http://helloworld.com, ht... [T1, T2, T3]
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因为在0.20.3版本中引发错误:
df = df.groupby(['id','name']).agg(lambda x: x.tolist())
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ValueError:函数不会减少
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