如何重写 PHP 类的构造函数?

Lil*_*aco 0 php oop

这是我的代码。我没有经验,所以请用简单的话告诉我答案。

<?php
function println($message) {
    echo "\n".$message;
}
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println 本质上是 echo 但在消息之前有一个 \n 。我只是习惯了Python 3,但不能使用print()。

class Car {
    public function __construct($name) {
    //If the constructor is that of a car, it will be said that a car was made.

        println("Car made!");
        $this->distance_drived = 0;
        $this->name = $name;
    }
    function introductory() {
        return "This car is called ".$this->name.".";
    }
}

class Battery {
    function __construct($max_capacity, $current_capacity) {
        echo "Constructed!";
        $this->max_capacity = $max_capacity;
        $this->current_capacity = $current_capacity;
    }
    function fill($amount) {
        if ($amount + $this->current_capacity >= $this->max_capacity) {
            $this->fill_full();
        } else {
            $this->current_capacity += $amount;
        }
    }
    function fill_full() {
        $this->current_capacity = $this->max_capacity;
    }
    function use_power($amount) {
        if ($amount + $this->current_capacity >= $this->max_capacity) {
            return $this->current_capacity;
            $this->current_capacity = 0;
        } else {
            $this->current_capacity -= $amount;
            return $amount;
        }
    }
    function check_percentage() {
        return ($this->current_capacity / $this->max_capacity) * 100;
    }
}

class ElectricCar extends Car {
    public function __construct($name, $max_capacity, $current_capacity, $power_per_km) {
        println("Electric car made!");

        //If the constructor is that of an electric car, it will be said that a car was made.

        $this->distance_drived = 0;
        $this->name = $name;
        println($max_capacity);
        $this->battery = new Battery($max_capacity, $current_capacity);
    }
    public function move($km) {
        $power_required = $km * $this->power_per_km;
        $used = $battery->use_power($power_required);
        $this->distance_drived += $used / $this->power_per_km;
    }
}

$toyota = new Car("Toyota 2017");
println($toyota->name);
println($toyota->introductory());
$tesla = new Car("Tesla Model S", 1000, 750, 5);
println($tesla->introductory());
println("Capacity is ".$tesla->battery->max_capacity);

?>
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我的主要问题是该消息仍然是 ElectricCar 中汽车的消息,因此 __construct() 没有改变。

Sal*_*tro 5

实际上,您已经覆盖了父构造函数,只需在子类中编写一个新的构造函数即可。当您不重写构造函数时,就会调用父构造函数。

从您的代码中我可以看到您正在将 Tesla 创建为汽车,而不是 ElectricCar,这就是您收到 Car 消息而不是 ElectricCar 消息的原因。

仅供参考当您希望子类构造函数扩展父类构造函数时,您要做的就是以这种方式调用父类构造函数

parent::__construct();
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