我有一个数据框stock_pick并尝试设置某些列的最后一行
stock_pick.iloc[-1]["Regime"] = 0
Run Code Online (Sandbox Code Playgroud)
结果是,
/home/prowler/analysis-toolkit/anaconda2/envs/py3.6/lib/python3.6/site-packages/pandas/core/indexing.py:179: SettingWithCopyWarning:
A value is trying to be set on a copy of a slice from a DataFrame
See the caveats in the documentation: http://pandas.pydata.org/pandas-docs/stable/indexing.html#indexing-view-versus-copy
self._setitem_with_indexer(indexer, value)
Run Code Online (Sandbox Code Playgroud)
选择值并将其分配给最后一行中的特定列的正确方法是什么?
您可以将其get_loc用作列的位置,并且可以使用DataFrame.iloc:
stock_pick.iloc[-1, stock_pick.columns.get_loc("Regime")] = 0
Run Code Online (Sandbox Code Playgroud)
另一种解决方案是选择依据,DataFrame.loc然后按位置选择索引[-1]:
stock_pick.loc[stock_pick.index[-1], "Regime"] = 0
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
3499 次 |
| 最近记录: |