如何在Android中检索联系人姓名和电话号码

Question

我正在尝试检索联系人列表,其中包含姓名和电话号码.我尝试以下代码:

 // Get a cursor over every contact.
    Cursor cursor = getContentResolver().query(People.CONTENT_URI, 
                                               null, null, null, null); 
    // Let the activity manage the cursor lifecycle.
    startManagingCursor(cursor);
    // Use the convenience properties to get the index of the columns
    int nameIdx = cursor.getColumnIndexOrThrow(People.NAME); 

    int phoneIdx = cursor. getColumnIndexOrThrow(People.NUMBER);
    String[] result = new String[cursor.getCount()];
    if (cursor.moveToFirst())
      do { 
        // Extract the name.
        String name = cursor.getString(nameIdx);
        // Extract the phone number.
        String phone = cursor.getString(phoneIdx);
        result[cursor.getPosition()] = name + "-" +" "+  phone;
      } while(cursor.moveToNext());

此代码应返回一个包含所有联系人姓名及其电话号码的数组,但这只返回联系人姓名并在电话号码中返回NULL,

示例输出:

 John - null

Answer 1

在Android清单中:

    <uses-permission android:name="android.permission.READ_CONTACTS" />

然后在活动中:

editText.setOnFocusChangeListener(new OnFocusChangeListener(){

            @Override
            public void onFocusChange(View v, boolean hasFocus) {
                if(hasFocus){
                    editText.setText("");   
                     Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
                     startActivityForResult(intent, PICK_CONTACT);
                }
            }           
        });

然后你必须抓住动作选择联系人的结果:

@Override 
public void onActivityResult(int reqCode, int resultCode, Intent data){ 
    super.onActivityResult(reqCode, resultCode, data);

    switch(reqCode)
    {
       case (PICK_CONTACT):
         if (resultCode == Activity.RESULT_OK)
         {
             Uri contactData = data.getData();
             Cursor c = managedQuery(contactData, null, null, null, null);
              if (c.moveToFirst())
              {
                  String id = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts._ID));

                  String hasPhone = c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));

                  if (hasPhone.equalsIgnoreCase("1")) 
                  {
                      Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null, 
                             ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id,null, null);
                      phones.moveToFirst();
                      String cNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                       Toast.makeText(getApplicationContext(), cNumber, Toast.LENGTH_SHORT).show();

                      String nameContact = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));

                      editText.setText(nameContact+ " "+ cNumber);
                  }
             }
       }
    }
}

Answer 2

不要使用已弃用的 API 访问，如下所示

        Cursor cursor = getContentResolver().
    query( Contacts.CONTENT_URI, 
            new String[]{Contacts.DISPLAY_NAME}, null, null,null);
    if(cursor!=null){
        while(cursor.moveToNext()){
            Cursor c = getContentResolver().query(Phone.CONTENT_URI, new String[]{Phone.NUMBER, Phone.TYPE}, 
                    " DISPLAY_NAME = '"+cursor.getString(cursor.getColumnIndex(Contacts.DISPLAY_NAME))+"'", null, null);
            while(c.moveToNext()){
                switch(c.getInt(c.getColumnIndex(Phone.TYPE))){
                case Phone.TYPE_MOBILE :
                case Phone.TYPE_HOME :
                case Phone.TYPE_WORK :
                case Phone.TYPE_OTHER :
                }
            }
        }
    }