H C*_*H C 5 django django-serializer django-rest-framework
我正在使用'rest_serializer'模块实现Django REST API框架:
当前输出为:
{
"count": 86,
"next": "http://127.0.0.1:8000/state/?page=2",
"previous": null,
"results": [
{
"state_name": "Alaska"
},
{
"state_name": "California"
},
...
]
}
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如何将其显示为json列表:
[
"Alaska",
"California",
...
]
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以下是我的序列化器:
from .models import States
from rest_framework import serializers
class StateSerializer(serializers.ModelSerializer):
class Meta:
model = State
fields = ('state_name',)
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view.py
class StateViewSet(viewsets.ModelViewSet):
"""
API endpoint that allows groups to be viewed or edited.
"""
queryset = States.objects.values('state_name').distinct();
serializer_class = StateSerializer
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这是我要做的:因为您想要为您的状态自定义序列化表单,我将实现一个自定义序列化程序:
class RawStateSerializer(serializers.BaseSerializer):
def to_representation(self, obj):
return obj.state_name
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然后你可以正常使用它来阅读:
class StateViewSet(viewsets.ModelViewSet):
queryset = States.objects.values('state_name').distinct();
serializer_class = RawStateSerializer
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请注意,它仅支持读取(它只会为 single 返回一个字符串,为GETlist返回一个字符串列表GET)。如果您还需要编写支持,则需要覆盖.to_internal_value()方法。
最后,如果您只需要用于列出组的特殊序列化程序,但需要用于其他操作的常规序列化程序,那么您将如何操作(基于我的这个答案):
class StateViewSet(viewsets.ModelViewSet):
queryset = States.objects.values('state_name').distinct();
def get_serializer_class(self):
if self.action == 'list':
return RawStateSerializer
return StateSerializer
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小智 1
您可以覆盖listmodelmixinlist提供的方法:
from rest_framework.response import Response
class StateViewSet(viewsets.ModelViewSet):
"""
API endpoint that allows groups to be viewed or edited.
"""
queryset = States.objects.values('state_name').distinct();
serializer_class = StateSerializer
def list(self, request, *args, **kwargs):
queryset = self.filter_queryset(self.get_queryset())
return Response(queryset.values_list('state_name', flat=True))
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