从 xml 配置中读取 spring yml 属性

Question

我正在尝试从 spring-bean.xml 中的 application.yml 读取属性，如下所示：

<bean name="#{bean.name}" />

是否可以 ？或者我应该指定我的 application.yml 文件的位置？

Answer 1

Yes It's Possible

For YAML Properties

1. You have to use YamlPropertiesFactoryBean

   <bean id="yamlProperties" class="org.springframework.beans.factory.config.YamlPropertiesFactoryBean">
       <property name="resources" value="classpath:application.yml"/>
   </bean>
   
   <context:property-placeholder properties-ref="yamlProperties"/>
   

2. Then define your property in src/main/resource/application.yaml

   bean:
      name: foo
   

3. Now use can use the property in xml to create a bean

   <bean name="${bean.name}"
   class="net.asifhossain.springmvcxml.web.FooBar"/>
   

Here's my complete XML config

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
                           http://www.springframework.org/schema/beans/spring-beans-4.3.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
    <bean id="yamlProperties" class="org.springframework.beans.factory.config.YamlPropertiesFactoryBean">
        <property name="resources" value="classpath:application.yaml"/>
    </bean>

    <context:property-placeholder properties-ref="yamlProperties"/>

    <bean name="${bean.name}" class="net.asifhossain.springmvcxml.web.FooBar"/>
</beans>