Avi*_*ran 1 android exoplayer exoplayer2.x
我正在尝试将手机中的媒体播放到ExoPlayer中。我正在从Environment.getExternalStorageDirectory().getAbsoluteFile();
每当我尝试播放媒体时-我都会收到此错误-
源错误com.google.android.exoplayer2.upstream.HttpDataSource $ HttpDataSourceException:无法连接到/storage/emulated/0/Download/big_buck_bunny_720p_1mb.mp4
也,
引起原因:java.net.MalformedURLException:无协议:/storage/emulated/0/Download/big_buck_bunny_720p_1mb.mp4
我在这里经过乌里 MediaSource mediaSource = buildMediaSource(Uri.parse(link));
这种方法正在使用Uri
private MediaSource buildMediaSource(Uri uri) {
DataSource.Factory dataSourceFactory = new
DefaultHttpDataSourceFactory("ua", BANDWIDTH_METER);
DashChunkSource.Factory dashChunkSourceFactory = new
DefaultDashChunkSource.Factory(dataSourceFactory);
return new DashMediaSource(uri, dataSourceFactory,
dashChunkSourceFactory, null, null);
}
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这就是我获得链接的方式
arrayList1 = video(Environment.getExternalStorageDirectory().getAbsoluteFile());
protected ArrayList<File> video(File file) {
File[] filename = file.listFiles();
ArrayList<File> arrayList2 = new ArrayList<File>();
try {
for (File file1 : filename) {
if (file1.isDirectory()) {
arrayList2.addAll(video(file1));
} else {
if (file1.getName().endsWith(".mp4")) {
arrayList2.add(file1);
}
}
}
}catch (Exception e){
}
return arrayList2;
}
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使用FileDataSource。以下代码段通过资产uri(例如file:///android_asset/video.mp4或其他文件uri)为mp4创建MediaSource:
private MediaSource buildMediaSource(Uri uri) {
DataSource.Factory dataSourceFactory = new FileDataSourceFactory();
return new ExtractorMediaSource(uri, dataSourceFactory,
new DefaultExtractorsFactory(), null, null);
}
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