joh*_*ith 0 xcode dictionary ios swift swift3
我在“self.email = (snapshot.value as! NSDictionary)["email"] as! String”行中收到错误,表示它无法转换“NSNull”类型的值。我该如何修复该错误?我认为既然我有一个函数 toAnyObject ,它就会将所有内容转换为字符串。
struct User {
var email: String!
var uid: String!
var ref: DatabaseReference!
var key: String = ""
init(snapshot: DataSnapshot) {
self.email = (snapshot.value as! NSDictionary)["email"] as! String
self.uid = (snapshot.value as! NSDictionary)["uid"] as! String
self.ref = snapshot.ref
self.key = snapshot.key
}
init(email: String, uid: String) {
self.email = email
self.uid = uid
self.ref = Database.database().reference()
}
func toAnyObject() -> [String: Any] {
return ["email":self.email, "uid":self.uid]
}
}
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正如 El Captain v2.0 指出的那样,不要强制解包一个值,否则nil你会崩溃。改用if let:
// if snap has a value, then you can use the value. Otherwise not, you can call an else if you want to.\nif let snap = snapshot.value as? [String:Any] { \n self.email = snap["email"] as! String \n}\nRun Code Online (Sandbox Code Playgroud)\n\n我也会跳过这个as! String,而是会这样做,以防万一你不\xc2\xb4t得到值email。
if let snap = snapshot.value as? [String:Any], let email = snap["email"] as? String { \n // Use email in here now\n print(email)\n}\nRun Code Online (Sandbox Code Playgroud)\n\n因此,如果您想获取其他字段,只需将它们添加到if-statement.