如何使用javascript确定HTMLScriptElement是否已完全加载?
如何在不使用onload或onreadystate更改事件的情况下确定动态加载的脚本是否已完成加载?
代码如下:
TOOL.loadScript = function (url, callback, reappend, deepSearch) {
var head, curr, child, tempScript, alreadyAppended, queue,
alreadyHandled, script, handler, loadFunc;
head = document.getElementsByTagName("head")[0];
tempScript = document.createElement("script");
tempScript.src = url;
alreadyAppended = false;
queue = [];
if (deepSearch) {
// search entire document
queue.push(document.firstElementChild);
}
else {
// just search the head element
queue.push(head);
}
while (queue.length !== 0) {
curr = queue.shift();
// add child nodes to queue
child = curr.firstElementChild;
if (child !== null && child !== undefined) {
queue.push(child);
child = child.nextElementSibling;
while (child !== null && child !== undefined) {
queue.push(child);
child = child.nextElementSibling;
}
}
if (curr.tagName !== null && curr.tagName !== undefined) {
if (curr.tagName.toLowerCase() === "script" && curr.src === tempScript.src) {
script = curr;
alreadyAppended = true;
break;
}
}
}
if (!alreadyAppended) {
script = document.createElement("script");
script.type = "text/javascript";
script.async = true;
script.src = url;
}
alreadyHandled = false;
handler = function (event) {
console.log("handling event...");
if (!alreadyHandled) {
if ((!event.readyState) || (event && (event.readyState === "loaded" || event.readyState === "complete"))) {
alreadyHandled = true;
callback.apply(script, [url]);
if (loadFunc) {
loadFunc.apply(script, arguments);
}
}
}
};
if (script.onreadystatechange === undefined) {
loadFunc = script.onload;
script.onload = handler;
}
else {
loadFunc = script.onreadystatechange;
script.onreadystatechange = handler;
}
Run Code Online (Sandbox Code Playgroud)
我需要帮助.我希望即使alreadyAppeneded === true已经加载了相同的脚本也会触发回调函数,但只有当该脚本完全加载时才会触发.
if (!alreadyAppended || (alreadyAppended && reappend)) {
head.appendChild(script);
}
};
Run Code Online (Sandbox Code Playgroud)
BOTTOM LINE:如何确定脚本是否已完成加载?如果需要,请问我问题.
谢谢.
惰性实现:创建一个数组,可用于将所有已加载脚本的源推送到其上,并在加载脚本时将其推送到列表中。每次,检查给定的 src 是否在数组中,如果在,则立即触发回调。
当案例被附加但未加载时,您如何处理它成为问题。如果您希望回调触发,但希望它在加载后触发,您可以创建一个关联数组,其中 src 作为键,脚本元素作为值。从那里,通过包装原始内容使 onload 或 onreadystatechange 触发两次,如下所示:
var temponload = element.onreadystatechange || element.onload;
if (element.onreadystatechange === undefined)
element.onload = function(e) { temponload(); temponload(); };
else
element.onreadystatechange = function (e) { temponload(); temponload(); };
Run Code Online (Sandbox Code Playgroud)
您可能还有其他代码需要连接到此代码,但这应该可以帮助您开始。
| 归档时间: |
|
| 查看次数: |
10580 次 |
| 最近记录: |