排序3个人的年龄

Question

/* to find the age of individuals according to youngest to oldest */

#include <stdio.h>

int main(void)
{
  int age1, age2, age3, youngest, middle, oldest;
  {
    printf ("Enter the age of the first individual: ");
    scanf  ("%d", &age1);
    printf ("Enter the age of the second individual: ");
    scanf  ("%d", &age2);
    printf ("Enter the age of the third individual: ");
    scanf  ("%d", &age3);
  }
  if (age1==age2==age3);
  {
    printf("All individuals have the same age of %d", &age1);
  }
  else
  {
    youngest = age1;

    if (age1 > age2)
      youngest = age2;
    if (age2 > age3)
      youngest = age3;

    middle = age1;

    if (age1 > age2)
      middle = age2;
    if (age2 < age3)
      middle = age2;

    oldest = age1;

    if (age1 < age2)
      oldest = age2;
    if (age2 < age3)
      oldest = age3;

    printf("%d is the youngest.\n", youngest);
    printf("%d is the middle.\n", middle);
    printf("%d is the oldest.\n", oldest);
  }
  return 0;
}

我一直在第21行得到错误,该错误表明我有一个'else'和之前的'if'.这里的任何专家都可以告诉我哪里出错了？如果我要删除'else',显示也有点奇怪.

Answer 1

在你的代码中

 if (age1==age2==age3);

是可怕的破碎.

两个要点,

• 像的表达age1==age2==age3是要么

  • 0 == age3 , 什么时候 age1 != age2
  • 1 == age3 , 什么时候 age1 == age2

  没有你想要的.

• 将;在结束if发言使得下一个块无条件的.

充其量,你可以改写相同的

 if ( ( age1 == age2 ) && ( age2 == age3) ) { .... }

在那之后,如果是

  printf("All individuals have the same age of %d", &age1);

你不需要传递变量的地址.事实上,这使得语句非常错误,将不兼容类型的参数传递给提供的转换说明符,这会导致未定义的行为.