将字符串拆分为迭代器

Question

python是否有内置(意味着在标准库中)对产生迭代器而不是列表的字符串进行拆分？我想到了很长的字符串,不需要消耗大部分字符串.

Answer 1

不直接拆分字符串,但re模块具有re.finditer()(和finditer()任何编译的正则表达式上的相应方法).

@Zero问了一个例子:

>>> import re
>>> s = "The quick    brown\nfox"
>>> for m in re.finditer('\S+', s):
...     print(m.span(), m.group(0))
... 
(0, 3) The
(4, 9) quick
(13, 18) brown
(19, 22) fox

Answer 2

像s.Lott一样,我不太清楚你想要什么.以下是可能有用的代码:

s = "This is a string."
for character in s:
    print character
for word in s.split(' '):
    print word

还有s.index()和s.find()用于查找下一个字符.

后来:好的,这样的事情.

>>> def tokenizer(s, c):
...     i = 0
...     while True:
...         try:
...             j = s.index(c, i)
...         except ValueError:
...             yield s[i:]
...             return
...         yield s[i:j]
...         i = j + 1
... 
>>> for w in tokenizer(s, ' '):
...     print w
... 
This
is
a
string.